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crimeas [40]
4 years ago
6

Hexane and heptane are miscible with each other in all proportions. In making a solution of them, is the entropy of the system i

ncreased, decreased, or close to zero, compared to the separate pure liquids?a. The entropy of the system is increased.b. The entropy of the system is decreased.c.The entropy of the system is close to zero.
Chemistry
1 answer:
Damm [24]4 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

A miscible solution is defined as the one in which two or more than two components are soluble with each other.

So, when hexane is added to heptane then both of them will mix with each other and hence they are miscible. This mixing will lead to formation of more number of ions into the solution as a result, more will be the disorder present in the solution.

As entropy is the degree of randomness present.

Hence, we can conclude that a solution of hexane and heptane will lead to an increase in entropy.

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Write the equilibrium constant expression for the reaction below.
kodGreya [7K]

Answer:

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

Explanation:

The equilibrium constant indicates the % of the yield reaction and can shows where the reaction is going to be equilibrated.

It works with molar concentrations on the equilibrium and it does not consider the solids compounds

Kc also can be modified by the time of the reaction.

This reaction is:

CS₂ (g) + 4 H₂O(g) ⇌ CH₄ (g) + 2H₂S (g)

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

8 0
3 years ago
Indicate what happens to the concentration of Pb2+ in each half cell
Taya2010 [7]

Answer:

Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below

The correct answer is (d) the left half-cell will decrease in concentration; and the right half-cell will increase in concentration.

Explanation:

The concentration of the Pb2+ increases in the oxidation half cell while the concentration of the Pb2+ decreases in the reduction half cell during the reaction.

In the Left Beaker (Left half cell), their is less concentration

Pb(s) ---> Pb2+(aq) + 2 e- Concentration of Pb2+(aq) increase ; Electrons going out from this side

In the Right Beaker (right half cell), their is more concentration

Pb2+(aq) + 2 e- ---> Pb(s) Concentration of Pb2+(aq) decrease ; Electrons coming in to this side

Electrons will flow from Left to Right direction.

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3 years ago
How many silver (Ag) atoms are in a silver bar that is 20.0 g? A. 1.3 3 1027 Ag atoms B. 6.02 3 1023 Ag atoms C. 1.1 3 1023 Ag a
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C. 1.1 3 1023 Ag atoms
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If 2.8X10⁻¹⁰% of the atoms of a radioactive isotope disintegrate in 1.0 yr, what is the decay constant of the process?
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Decay constant, proportionality between the size of a population of radioactive atoms and the rate at which the population decreases because of radioactive decay.

<h3>What is decay constant value?</h3>

The rate of disintegration is proportional to the number of atoms at any point in time and the constant of proportionality is called the radioactivity decay constant. The radioactive decay constant for Radium B is approximately 4.3 × 10−4 s−1.

<h3>What is decay constant unit?</h3>

Definition. The decay constant (symbol: λ and units: s−1 or a−1) of a radioactive nuclide is its probability of decay per unit time. The number of parent nuclides P therefore decreases with time t as dP/P dt = −λ. The energies involved in the binding of protons and neutrons by the nuclear forces are ca.

Learn more about decay constant here:

<h3>brainly.com/question/16623902</h3><h3 /><h3>#SPJ4</h3>

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