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crimeas [40]
4 years ago
6

Hexane and heptane are miscible with each other in all proportions. In making a solution of them, is the entropy of the system i

ncreased, decreased, or close to zero, compared to the separate pure liquids?a. The entropy of the system is increased.b. The entropy of the system is decreased.c.The entropy of the system is close to zero.
Chemistry
1 answer:
Damm [24]4 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

A miscible solution is defined as the one in which two or more than two components are soluble with each other.

So, when hexane is added to heptane then both of them will mix with each other and hence they are miscible. This mixing will lead to formation of more number of ions into the solution as a result, more will be the disorder present in the solution.

As entropy is the degree of randomness present.

Hence, we can conclude that a solution of hexane and heptane will lead to an increase in entropy.

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Would you expect a reaction to occur with Hydrogen gas and Copper (II) chloride?
amid [387]
<h3>Yes</h3>

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5 0
3 years ago
How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas (O2) using the following reaction by completing
mezya [45]

<u>Answer:</u> 6 moles of KClO_3 will be decomposed.

<u>Explanation:</u>

We are given:

Moles of oxygen gas produced = 9 moles

The chemical equation for the decomposition of KClO_3 follows:

2KClO_3\rightarrow 2KCl+3O_2

By the stoichiometry of the reaction:

If 3 moles of oxygen gas is produced by 2 moles of KClO_3

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Hence, 6 moles of KClO_3 will be decomposed.

4 0
3 years ago
What is the final volume of a 400.0 mL gas sample that is subjected to a
mestny [16]

Answer: 0.27L

Explanation:

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(If 1000mL = 1L

400.0 mL = 400.0/1000 = 0.4 L)

Original temperature T1 = 22.0 °C

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(22.0 °C + 273 = 295K)

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Convert pressure of 1000mmHg to atm

(If 760mmHg = 1 atm

1000mmHg = 1000/760 = 1.316 atm)

New volume V2 = ?

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New pressure P2 = 2 atm

Since pressure, volume and temperature are involved, apply the general gas equation

(P1V1)T1 = (P2V2)/T2

(1.316 atm x 0.4 L) /295K = (2 atm x V2) /303K

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Cross multiply

0.526 atmL x 303K = 2V2 x 295K

159.47 = 590V2

Divide both sides by 590

159.47/590 = 590V2/590

0.27 L = V2

Thus, the final volume of the gas is 0.27L

7 0
3 years ago
Which of the following are properties of ionic compounds?
navik [9.2K]
The answer would be b.
4 0
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Complete the equation below for the neutralization reaction by writing the formula ofeach product. 40) KOH(aq) HCl(aq)
Montano1993 [528]
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hope this helps!

</span>
6 0
3 years ago
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