Number D both H and OH ions
Reichsteins substance if I remember correctly.
Hope this helped! :)
- Juju
First step is to balance the reaction equation. Hence we get
P4 + 5 O2 => 2 P2O5
Second, we calculate the amounts we start with
P4: 112 g = 112 g/ 124 g/mol – 0.903 mol
O2: 112 g = 112 g / 32 g/mol = 3.5 mol
Lastly, we calculate the amount of P2O5 produced.
2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4
mol of P2O5.
This is 1.4 * (31*2 + 16*5) = 198.8 g
Answer:
% weight of nickle = 24 %
Explanation:
molar mass of Nickel Sulfamate (Ni(SO₃NH₂)₂) = 250.87 g/mol
Solution
1st we write down the molar mass of Ni
molar mass of Ni = 59 g/mol
now we write down the number of moles of Ni in (Ni(SO₃NH₂)₂)
number of moles of Ni = 1 mol
Now we calculate the mass of nickle present in (Ni(SO₃NH₂)₂)
<em> mass = moles × molar mass</em>
mass = 1 mol × 59 g/mol
mass = 59 g
now we calculate the % weight of nickle in (Ni(SO₃NH₂)₂)
<em> % weight = (weight of element ÷ total weight) × 100</em>
% weight of nickle = (59 ÷ 250.87) × 100
% weight of nickle = 0.24 × 100
% weight of nickle = 24 %
