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3 years ago

12

If a point P(–1, –1) is reflected across the line y = –2, what are the coordinates of its reflection image?

1 answer:

Ksivusya [100]3 years ago

8 0

Since the line of refrection is a horizontal line, the x-coordinate of the image will be the same as the x-coordinate of the point P(-1, -1). P(-1, -1) is one unit above the line y = -2, hence the image will be one unit below the line y = -2. Therefore the coordinate of the image is (-1, -3)

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Answer:

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Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

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$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

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$x = \frac{x_1 + x_2}{2}$

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$5 = \frac{-6 + x_2}{2}$

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$2 * 5 = \frac{-6 + x_2}{2} * 2$

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$6 + 10 = -6 +6 + x_2$

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Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

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$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

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