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blsea [12.9K]
4 years ago
5

3x2 +4=0 whats the answer?

Mathematics
2 answers:
aleksklad [387]4 years ago
7 0

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

                Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Lets do this step by step.

Simplify \frac{3x - 2}{x} -4.

To write -4 as a fraction with a common denominator, multiply by \frac{x}{x}

\frac{3x - 2}{x} - 4 . \frac{x}{x} > 0

Combine  -4 and \frac{x}{x}.

\frac{3x - 2}{x} + \frac{-4x}{x} > 0

Combine the numerators over the common denominator.

\frac{3x - 2 -4x}{x} > 0

Subtract 4x from 3x.

\frac{-x -2}{x} > 0

Factor -1 out of -x.

\frac{-(-x) -2}{x} >0

Rewirte -2 as -1 (2).

\frac{-(x -1 (2)}{x} > 0

Factor -1 out of - (x) - 1 (2).

\frac{-(x + 2)}{x} >0

Simplify the Expression.

_______________

Rewrite - ( x + 2 ) as -1 ( x + 2 ) .

\frac{-1 ( x+ 2)}{x} > 0

Move the negative in front of the fraction.

- \frac{x + 2}{x} > 0

Then your going to find all the values where the expression switches from negative to positive by setting each factor equal to 0  and solving.

x = 0\\x + 2 = 0

Subtract 2 from both sides of the equation.

x = -2

Solve for each factor to find the values where the absolute value expression goes from negative to positive.

x = 0 \\x = -2

Consolidate the solutions.

x = 0, -2

________________

Find the domain of \frac{3x - 2}{x} -4

_________________

Set the denominator in \frac{3x - 2}{x}  equal to 0 to find where the expression is undefined.

x = 0

The domain is all values of x that make the expression defined.

( - ∞, 0 ) ∪ ( 0 , ∞)

Use each root to create test intervals.

x < -2 \\-2 < x < 0 \\x > 0

|Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.|

Test a value on the interval -2 < x < 0 to see if it makes the inequality true.

Ans : True

Test a value on the interval x > 0 to see if it makes the inequality true.

Ans : False

Test a value on the interval x < -2  to see if it makes the inequality true.

Ans : False

Compare the intervals to determine which ones satisfy the original inequality.

x < -2 = False\\-2 < x < 0 = True\\x > 0 = False

The solution consists of all of the true intervals.

-2 < x < 0

The result can be shown in multiple forms.

Inequality Form: -2  < x< 0

Interval Notation: ( -2 , 0 )

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

Rufina [12.5K]4 years ago
3 0

Answer:

False

Step-by-step explanation:

3x2 is 6 and 6 +4 is not 0 it is ten 10 norder of operations

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HELP PLZZ will give brainliest &lt;3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
3 years ago
Your class earned $120.00 Saturday afternoon by washing cars to raise money for the class trip. This is 1/4 of the money needed
Ilya [14]

Answer:

$360.00

(I hope this was helpful)

5 0
3 years ago
Use what you know about the angle sum theorem for triangles and your algebra skills to solve for x and find the measure of all t
melomori [17]

Answer:

2x° = 45°, 3x° = 67.5°

Step-by-step explanation:

Sum of angles in a triangle = 180°

2x+3x+3x=180°

8x=180°

x=22.5°

2x=22.5°x2=45°

3x=22.5°x3=67.5°

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3 years ago
Which point represents the opposite of -2?
vekshin1

Answer:

your answer is point D represent

8 0
3 years ago
A random sample of 864 births in a state included 426 boys. Construct a 95% confidence interval estimate of the proportion of bo
oksian1 [2.3K]

Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:

n = 864, \pi = \frac{426}{864} = 0.493

Then, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 - 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.46

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 + 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.526

The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
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