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3 years ago

Help please!! Solve for x, show all work. Thanks!

Mathematics

1 answer:

ELEN [110]3 years ago

8 0

Answer: 54

Step-by-step explanation:

The second term 3/2 loga 9 = loga 9^3/2 = loga 27

The RHS = loga 27 x 2 = loga 54

So loga x = loga 54

x = 54

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Simplify 27+2(6+x) 1. 35+x^2 2.39+2x 3.27+12x 4.29+8x

Effectus [21]

Answer:

39 + 2x

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

There are 16 white balloons, 24 red balloons. Each arrangement must be identical. What is the greatest number of arrangements yo

katovenus [111]

Answer:

Step-by-step explanation:

hope i helped have a verey good day

4 0

3 years ago

A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di

Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, $\mu$ = 1.3 cm and Standard deviation, $\sigma$ = 0.01 cm

Also, since distribution is normal;

Z = $\frac{X -\mu}{\sigma}$ ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

P(X < 1.33) = P( $\frac{X -\mu}{\sigma}$ < $\frac{1.33 -1.3}{0.01}$ ) = P(Z < 3) = 0.99865

P(X <= 1.27) = P( $\frac{X -\mu}{\sigma}$ < $\frac{1.27 -1.3}{0.01}$ ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

= 0.00135

P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0

3 years ago

When 4 is added to three times of a number, the answer is the same as subtracting 2 from the number. What is the number ?

Orlov [11]

Answer:

- 3

Step-by-step explanation:

let n be the number , then

3n + 4 = n - 2 ( subtract n from both sides )

2n + 4 = - 2 ( subtract 4 from both sides )

2n = - 6 ( divide both sides by 2 )

n = - 3

The number is - 3

7 0

3 years ago

Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was

andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 100, p = 0.42$

92% confidence level

So $\alpha = 0.08$ , z is the value of Z that has a pvalue of $1 - \frac{0.08}{2} = 0.96$ , so $Z = 1.75$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064$

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0

3 years ago