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Colt1911 [192]
3 years ago
13

According to the properties of inequality, when should the inequality symbol be reversed when solving a two-step any quality in

the form below? A X plus B > C
Mathematics
2 answers:
nika2105 [10]3 years ago
7 0

Answer:When A is negative(b)

Step-by-step explanation:

just did it on edg

Marina86 [1]3 years ago
3 0

According to the properties of inequality, we reverse the inequality symbol when we add or multiply by any negative number

Given inequality is Ax + B > C

In the first step, we subtract B from both sides

Ax + B > C

Ax + B - B > C - B

Ax > C - B

Now to remove A we divide by A on both sides

If A is negative then the reverse the inequality sign

When A is negative then > symbol becomes < symbol

so the inequality symbol be reversed when the value of A is negative

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The polynomial x2 + 7x – 44 can be factored.
Virty [35]

Answer:

(x-4)(x+11)

Step-by-step explanation:

(x-4)(x+11)

x^2-4x+11x-44

x^2+7x-44

Ding Dong!

5 0
2 years ago
–6 + (–12)<br><br> Evaluate the expression
Bezzdna [24]

Answer:

-18

Step-by-step explanation:

You can basically just drop the plus sign and remove the parenthesis because the plus sign doesn't alter negatives.

-6+(-12)

-6-12= -18

6 0
3 years ago
Read 2 more answers
4. A company manufactures tires to meet the annual demand of 125,000 production runs. One production run involves producing 100
lyudmila [28]

Answer:

a) Economic order or production quantity = 2,500 tires.

Number of production runs in a year = 50 runs

Hence, 2,500 tires should be produced in each of the 50 runs in a year to minimize total cost.

b) Minimum total inventory cost = Tsh 30,000

Step-by-step explanation:

The total cost for the tire production firm will be a sum of the total production cost and total inventory cost.

Total cost = Total Production cost + Total inventory cost

Total Production Cost = (Number of production runs in a year) × (Setup Cost of one production run)

Number of production runs in a year = (Annual demand)/(Number of units produced per production run)

Let the annual demand = D

Number of units produced per production run = Q

Setup Cost of one production run = S

Number of production runs in a year = (D/Q)

Total Production Cost = (DS/Q)

Total inventory Cost = (Average inventory level) × (Cost of holding 1 unit in inventory)

Average inventory level is usually assumed to be half of the number of units in a production run = (Q/2)

Cost of Holding a unit of product in inventory = H

Total inventory Cost = (QH/2)

Total cost = TC = (DS/Q) + (QH/2)

At minimum cost, (dTC/dQ) = 0

(dTC/dQ) = -(DS/Q²) + (H/2) = 0

(DS/Q²) = (H/2)

Q² = (2DS/H)

Hence,

Economic order/production quantity = Q = √(2DS/H)

For this question

D = Annual demand = 125,000 tires

S = Setup cost for one production run = Tsh 600

H = Holding cost for one unit in inventory = Tsh 24

Q = √(2×125000×600/24) = 2,500 units

Number of production runs in a year = (D/Q) = (125000/2500) = 50 production runs.

b) Total Inventory Cost = (QH/2)

At minimum total inventory cost, Q = 2,500

Minimum total inventory cost = (2500×24/2) = Tsh 30,000

Hope this Helps!!!

4 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%20%286-5p%29" id="TexFormula1" title="\frac{2}{5} (6-5p)" alt="\
weeeeeb [17]
Answer:
12/5 - 2p

Explanation:

2/5(6 - 5p)
2 • 6/5 + 2 • -5p
12/5 - 10p/5
12/5 - 2p
8 0
3 years ago
LCM OF 2.2 AND 5 NEED HELP ASAP PLEASE STUPID HOME WORK WISH IT NEVER EXISTED!
Alexxandr [17]

The <em>correct answer</em> is:

11

Explanation:

To find the LCM, we first find the prime factorization of each number:

2.2=2\times1.1 \\ \\5=5\times 1

We look for common factors first. There are none, except for 1, which is a factor of every number. Next we multiply the uncommon factors:

2(5)(1.1) = 10(1.1) = 11

The LCM is 11.

6 0
2 years ago
Read 2 more answers
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