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Genrish500 [490]
3 years ago
7

How do you work out this equation

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

x is equal to negative one, and y is equal to negative four.

Step-by-step explanation:

You can do this by solving one of the equations by either x or y, then substituting it into the other.  Let's solve the second one for y:

2y = 3x - 5\\y = \frac{3x - 5}{2}

Now we'll substitute that into the first equation:

9x - 2y = -1\\9x - 2(\frac{3x - 5}{2}) = -1\\9x - 3x + 5 = -1\\6x + 5 = -1\\6x = -6\\x = -1

So we now know that x is equal to -1.  We can simply substitute that into one of the original equations to find y:

2y = 3x - 5\\2y = 3(-1) - 5\\2y = -3 - 5\\2y = -8\\y = -4

We now know that x is equal to -1, and y is equal to -4.  We can also check our answer by plugging that -4 into the other equation, and see if we still get -1:

9x - 2y = -1\\9x - 2(-4) = -1\\9x + 8 = -1\\9x = -1 - 8\\9x = -9\\x = -1

So we know that our answer is correct.

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❖ There are 2 terms in 5x - 2. Each number (including the variable) counts as a term.

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Un aljibe de 12.4 m de profundidad se encuentra totalmente lleno de agua. ¿Cual es la presión en el fundo debido únicamente al p
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Answer:

a) p = 121644 Pa

b) p_{T} = 221644 Pa  

Step-by-step explanation:

a) La presión en el fondo debido únicamente al peso del agua se puede calcular usando la siguiente ecuación:

p = \rho gh

En donde:

ρ: es la densidad del agua = 1000 kg/m³

g: es la gravedad = 9.81 m/s²

h: es la profundidad = 12.4 m

p = \rho gh = 1000 kg/m^{3}*9.81 m/s^{2}*12.4 m = 121644 Pa

Entonces, la presión en el fondo debido al agua es 121644 Pa.

b) Para hallar la presión total en el fondo debemos ahora considerar la presión atmosférica:

p_{T} = p_{0} + \rho gh  

En donde p₀ es la presión atomsférica = 75 cmHg

p_{T} = 750 mmHg\frac{1 Pa}{0.0075 mmHg} + 121644 Pa = 221644 Pa

Por lo tanto, la presión total en el fondo es 221644 Pa.

Espero que te sea de utilidad!

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