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3 years ago

Answer all of these 50 points and brainliest

Mathematics

2 answers:

Andreas93 [3]3 years ago

7 0

7. -9 5/8

8. 3/14

9. 1

10. -2 7/8

11. 18/31

12. -16/27

1. -9/10

2. 1 17/21

3 -57/14

4. 29/30

5. 3 9/10

6. 5 17/24

Brainliest please

Stella [2.4K]3 years ago

6 0

It already got answered F

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A trail mix has 1/2 cup of raisins and 2/3 cup of peanuts. Witch ingredient has the great amount?

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Answer:

Peanuts

Step-by-step explanation:

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3 years ago

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5 over 4 n plus 5 equals 20

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N=18.75
because you have to work backwords

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4 years ago

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The mean number of automobiles entering a mountain tunnel per two-minute period is one. An excessive number of cars entering the

viva [34]

Answer:

A Poisson model seems reasonable for this problem, since we have the mean during the time interval.

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x)=\frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The mean number of automobiles entering a mountain tunnel per two-minute period is one.

This means that $\mu = 1$ .

For a Poisson model to be reasonable, we only need the mean during the time interval. So yes, a Poisson model seems reasonable for this problem.

Find the probability that the number of autos entering the tunnel during a two-minute period exceeds three.

We want to find $P(X>3)$

Either this number is less or equal to 3, or it exceeds 3. The sum of the probabilities is decimal 1. So:

$P(X \leq 3) + P(X > 3) = 1$

$P(X > 3) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1}*1^{0}}{(0)!} = 0.3679$

$P(X = 1) = \frac{e^{-1}*1^{1}}{(1)!} = 0.3679$

$P(X = 2) = \frac{e^{-1}*1^{2}}{(2)!} = 0.1839$

$P(X = 3) = \frac{e^{-1}*1^{3}}{(3)!} = 0.0613$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3679 + 0.3679 + 0.1839 + 0.0613 = 0.981$

Finally

$P(X > 3) = 1 - P(X \leq 3) = 1 - 0.981 = 0.019$

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

8 0

3 years ago

I will give Brainiest if your right

Monica [59]

Answer:

Step-by-step explanation:

sum of 15 and -6 is 11

-3 times -2 is 6 because the negatives cancel out

6 plus the 5 left in the parenthesis is 11

brainiest pls

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3 years ago

A.Two friends share 76 blueberries

Anna71 [15]

They would have to split apart the group with 6 blueberries. Each friend would get three blueberries from this group.

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3 years ago