A=lw
42xy^3=(14xy)l
isolate l
divide both sides by 14xy to isolate l
(42xy^3)/ (14xy)=14xy / 14xy *l
the 14xy in the right cancel out
now you have:
42xy^3/14xy=l
42/14= 3, now just do division of powers for xy
x-x =0x, y^3-y= y^2
therefore the answer is 3y^2

6 0

3 years ago

Iodine-125 has a daily decay rate of about 1%. How many milligrams of a 500 mg sample will remain after 300 days? Round the answ

Amanda [17]

So.. in this case, the starting amount is the 500mg sample... and the rate of decay, negative rate, is 1%, and at the time, the elapsed days is 0, to t = 0, P = 400

$\bf \qquad \textit{Amount for Exponential change}\\\\
A=P(1\pm r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{starting amount}\to &500\\
r=rate\to 1\%\to \frac{1}{100}\to &0.01\\
t=\textit{elapsed period}\to &300\\
\end{cases}
\\\\\\
A=500(1-0.01)^{300}$

7 0

3 years ago

Read 2 more answers

What's the estimate for 2-9

andrew11 [14]

The estimate between 2 and 9 is 7

5 0

3 years ago