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Luden [163]
3 years ago
8

What is the area of a circle with a radius of 1.5 centimeters? Use 3.14 as an approximation for pi.

Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0

The answer to this question is B


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Find the product.<br><br><br> (−7)(8) =
Inga [223]

Answer:-56

Step-by-step explanation:The product is your answer

4 0
3 years ago
The product 3 and a number x is 2/3. What is the value of x? A. X=7/3 B. x=2/9 C. x=2 D. X= 2 1/3
BabaBlast [244]

Answer:

the answer is C.

Step-by-step explanation:

3(2/3)

=3×2/3

=2×3/3

=2

7 0
3 years ago
On Thursday the high temperature was 0 °C. If it was three degrees colder on Friday, what was the temperature?
Rina8888 [55]

Answer:

-3 degrees C

Step-by-step explanation:

We need to subtract 3 degrees from Thursdays temperature

0 - 3

-3 degrees C

8 0
3 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
Juanita is watering her lawn using the water stored in her rainwater tank the water in the tank drops 1/3 inch every 10 minutes
Ilya [14]
<span>Juanita is watering her lawn using the water that is stored by rainwater.
=> the water in the tank drops 1/3 inch in every 10 minutes she waters.
=> The tanks water level is 4 feet.
Question : Number of days can Juanita waters is she waters 15 minutes per day.
=> 4 feet is the total amount of water = 1 ft = 12 inches
=> 48 inches in total
=> 1/3 inch is used every 10 minutes = 0.33 inches
=> she waters 15 minutes per day = 0.495 inches in every 15 minutes
Solution
=> 48 inches / 0.495 inches per day
=> 96.97
So Juanita can use all the water in water tank for approximately 97 days.</span>



8 0
3 years ago
Read 2 more answers
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