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3 years ago

11

one rectangle has a length 10 cm and width 5 cm the second rectangle has length 12 cm and width 4 cm are the two rectangles simi

lar explain

1 answer:

tatuchka [14]3 years ago

8 0

Answer:

No, they aren't similar.

Step-by-step explanation:

<u><em>Let's take the proportionality of their sides to check whether they are similar or not:</em></u>

$\frac{10}{5} = \frac{12}{4}$

=> 2 ≠ 3

So, they are not similar.

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$\huge\text{Hey there!}$

$\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}$

$\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}$

$\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}$

$\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}$

$\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}$

$\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}$

$\mathsf{= \dfrac{27+14}{30}}$

$\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}$

$\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}$

$\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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