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VikaD [51]
2 years ago
6

Which system of equations has no solutions? 9 NW AUOVO 5 -NW A o Voor 1 o 1 2 3 4 5 6 7 8 9 O 1 2 3 4 5 6 7 8 9 X O O O O MN 7.

6 5 NW A UV00 1 ol 1 2 3 4 5 6 7 8 9 o эх 1 2 3 4 5 6 7 8 9 X​

Mathematics
2 answers:
Burka [1]2 years ago
5 0

Answer:

a and b if not c

Step-by-step explanation:

dusya [7]2 years ago
3 0

Answer:

the one with one line and the one that is parallel, Basically the two on top^_^

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Molodets [167]
B is the answer

You should get the app CY math
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3 years ago
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Whats the vertex of a parabola?<br> Round to the nearest hundredth.
olya-2409 [2.1K]

Answer:

To get the x-intercept we need the equation of the parabola;

the vertex form of the equation is given by:

y=a(x-h)^2+k

where:

(2,13) is the vertex:

Therefore;

y=a(x-2)^2+13

when x=0, y=5

Therefore the value of a will be:

5=a(0-2)^2+13

5-13=4a

4a=-8

a=-2

therefore the equation of the parabola will be:

y=-2(x-2)^2+13

y=-2x^2+8x+5

the x-intercept will be:

x=2-sqrt(7.5)

or

x=2+sqrt(7.5)

Step-by-step explanation:

4 0
3 years ago
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Describe how to compare the two decimals 0.6 and 0.8
Dovator [93]

Answer:

they are 0.2 apart from each other and can easily be shown on a number line

Step-by-step explanation:

8 0
3 years ago
Help please im marking brainliest
Strike441 [17]

The surface area of the triangular prism is of 140 cm².

<h3>What is the surface area of a prism?</h3>

It is the sum of the areas of all faces of a prism. In this problem, the prism has these following faces:

  • One rectangle of dimensions 8 cm and 6 + 4 + 5 = 15 cm.
  • Two right triangles with sides 4 cm and 5 cm.

For a rectangle, the area is given by the multiplication of the dimensions, hence:

Ar = 8 x 15 = 120 cm²

For each right triangle, the area is given by half the multiplication of the sides, hence:

At = 2 x 0.5 x 4 x 5 = 20 cm².

Then the surface area of the prism is:

S = 120 cm² + 20 cm² = 140 cm².

More can be learned about surface area at brainly.com/question/28123954

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3 0
2 years ago
A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?
DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals 2.20\times 10^{8}\,Pa. The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress (\sigma), measured in pascals, in the wire with circular cross-section is:

\sigma = \frac{4\cdot F}{\pi\cdot D^{2}} (1)

Where:

F - Axial force, measured in newtons.

D - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that F = 800\,N and D = 0.002\,m, then the axial stress experimented by the titanium wire is:

\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}

\sigma \approx 2.546\times 10^{8}\,Pa

Since stress is greater than ultimate strength, the wire will break.

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3 years ago
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