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3 years ago

14. What is the simplified form of (5x2 + 11x - 9) - (2x - 3x + 5)?

Mathematics

2 answers:

krok68 [10]3 years ago

6 0

Answer:5x2+12x-14

Step-by-step explanation:

(5x2+11x-9)-(2x-3x+5)

5x2+11x-9-2x+3x-5

5x2+12x-14

Tasya [4]3 years ago

5 0

$(5x^2 + 11x - 9) - (2x - 3x + 5)=5x^2+11x-9-2x+3x-5=5x^2+12x-14$

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$(5x^2 + 11x - 9) - (2x^2 - 3x + 5)=5x^2+11x-9-2x^2+3x-5=3x^2+14x-14$

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6 0

3 years ago

In △ABC acute angles are in the ratio 5:1, i.e. ∠BAC:∠ABC = 5:1. If CH is an altitude and CL is an angle bisector, find m∠HCL.

tekilochka [14]

If $m\angle BAC:m\angle ABC=5:1,$ then $m\angla BAC=(5x)^{\circ},\ m\angle ABC=x^{\circ}.$

The sum of the measures of the interior angles of the triangle is always 180°, then

$m\angle ACB=180^{\circ}-x^{\circ}-(5x)^{\circ}=180^{\circ}-(6x)^{\circ}.$

Since CL is bisector, then

$m\angle BCL=m\angle ACL=\dfrac{180^{\circ}-(6x)^{\circ}}{2}=90^{\circ}-(3x)^{\circ}.$

Consider right triangle ACH. In this triangle

$m\angle ACH=180^{\circ}-90^{\circ}-(5x)^{\circ}=90^{\circ}-(5x)^{\circ}.$

Now angle HCL has measure

$m\angle HCL=m\angle ACL-m\angle ACH=90^{\circ}-(3x)^{\circ}-(90^{\circ}-(5x)^{\circ})=(2x)^{\circ}=2m\angle ABC.$

Answer: $m\angle HCL=2m\angle ABC.$

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4 years ago

14. What is the simplified form of (5x2 + 11x - 9) - (2x - 3x + 5)?​

14. What is the simplified form of (5x2 + 11x - 9) - (2x - 3x + 5)?