Answer:
<em>The car will be moving at 5.48 m/s at the bottom of the hill</em>
Explanation:
<u>Principle of Conservation of Mechanical Energy</u>
In the absence of friction, the total mechanical energy is conserved. That means that
is constant, being U the potential energy and K the kinetic energy
U=mgh
When the car is at the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.
The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.
We are given the initial potential energy U=45 J. It all is transformed to kinetic energy at the bottom of the hill, thus:
Multiplying by 2:
Dividing by m:
Taking square roots:
v = 5.48 m/s
The car will be moving at 5.48 m/s at the bottom of the hill
K= fx => f = k/x => 50N/100cm / 10 cm = 5/10= 0.5 N
Answer:
a) 2.933 m
b) 4.534 m
Explanation:
We're given the equation
v(t) = -0.4t² + 2t
If we're to find the distance, then we'd have to integrate the velocity, since integration of velocity gives distance, just as differentiation of distance gives velocity.
See attachment for the calculations
The conclusion of the attachment will be
7.467 - 2.933 and that is 4.534 m
Thus, The distance it travels in the second 2 sec is 4.534 m
Answer:absorbs and emits electromagnetic radiation at all wavelengths
Explanation:
A blackbody is a believed to be a perfect absorber and reflector of radiation. Blackbody, in physics, refers to a surface that absorbs all radiant energy that falls on it. It is supposed that because incident visible light will be absorbed rather than reflected, the surface will appear black.
Answer:
HCP
Extra -> BCC the most, FCC between
Explanation:
