In physics, there are already derived equation that are based on Newton's Law of Motions. The rectilinear motions at constant acceleration have the following equations:
x = v₁t + 1/2 at²
a = (v₂-v₁)/t
where
x is the distance travelled
v₁ is the initial velocity
v₂ is the final velocity
a is the acceleration
t is the time
Now, we solve first the second equation. Since it mentions that the car comes eventually to a stop, v₂ = 0. Then,
-5 = (0-v₁)/t
-5t = -v₁
v₁ = 5t
We use this new equation to substitute to the first one:
x = v₁t + 1/2 at²
15 = 5t(t) + 1/2(-5)t²
15 = 5t² - 5/2 t²
15 = 5/2 t²
5t² = 30
t² = 30/5 = 6
t = √6 = 2.45
Therefore, the time it took to travel 15 m at a deceleration of -5 m/s² is 2.45 seconds.
Answer:
weeds out the weak, sick, and old by killing them
Answer:
Newton's Laws Applied to Collisions. Newton's third law of motion is naturally applied to collisions between two objects. ... Thus, if the colliding objects have unequal mass, they will have unequal accelerations as a result of the contact force that results during the collision.
Explanation:
De broglie wavelength, 
, where h is the Planck's constant, m is the mass and v is the velocity.
Mass of hydrogen atom, 
v = 440 m/s
Substituting
Wavelength 
So the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm
B is the right answer glad I could help !!
