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zmey [24]
3 years ago
6

the engine of a car of amass of 2000 kg produced a force of 15000N find the acceleration of the car​

Physics
1 answer:
weqwewe [10]3 years ago
3 0
I believe the answer would be 7.5 m/s^2
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What happens to the object if the line crosses the x-axis from the positive portion of a velocity versus time diagram?
stealth61 [152]

Answer:

A velocity time graph shows the change of velocity of an object with respect ot time. If the slope of the graph is increasing in the postive region, it means that the velocity is changing, if the slope is decreasing, it means the the velocity is decreasing, but the object is moving in the same direction (positve direction).

If this slope intersects the graph at x-axis, it means that the body has 0 velocity and has become still. After that, if the line enters in the negative region, it means that its velocity is started to increases again, but the body is movinging in the opposite direction (negative direction)

7 0
3 years ago
2
timama [110]

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

a =  \frac{f}{m}

4 0
3 years ago
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Impulse equals?<br> A) momentum x velocity<br> B) momentum x time<br> C) mass x velocity
mina [271]

Answer:

B

Explanation:

The impulse experienced by an object is the force•time.

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3 years ago
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A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur
Nonamiya [84]

Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

5 0
3 years ago
1. A man is running on the straight road with the uniform velocity
Rufina [12.5K]
None he is undergoing constant uniform velocity. Acceleration is the rate of change of velocity
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