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4 years ago

Which statement best describes plastic's ability to conduct electricity?

2 answers:

3 0

<span>They are poor insulators because the electrons in the atom are tightly bound and unable to move between other atoms.
</span>

Kazeer [188]4 years ago

3 0

The real answer is D... the electrons can move freely between the different energy levels within the atom....

You might be interested in

An astrophysicist mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them

Alexandra [31]

Answer:

1 / i + 1 / o = 1 / f thin lens equations

i = o f / (o - f) rearranging

Lens 1: object = 30 cm f = 15.2 cm

i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm

o2 = 40.2 - 30/8 = 9.4 cm distance of image 1 from lens 2

i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm

The final image is 24.6 cm to the left of lens 2

The first image is inverted

The second image is erect (as seen from the first image)

So the final image is inverted

M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69

7 0

3 years ago

A student walks downstairs to class. Which statement correctly describes the types of energy the student has at the top of the s

AveGali [126]

Answer:

D potential energy at the top of the stairs, kinetic energy as she walks down

Explanation:

The potential energy of a body is the energy due to the position of the body.

At the top of the stair case, the student is at a significant height.

Kinetic energy is the energy due to the motion of the body.

As the student descends, the potential energy is changed to kinetic energy.

To find the potential energy;

P.E = mgH

m is the mass

g is the acceleration due to gravity

H is the height of the body

To find the kinetic energy;

K.E = $\frac{1}{2}$ m v²

m is the mass

v is the velocity

8 0

3 years ago

What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C tes

bagirrra123 [75]

The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

<h3>Electric field on the master charge</h3>

E = kq/r²

where;

q is magnitude of master charge
r is distance of separation
k is Coulomb's constant

E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

<h3>Force on the test charge</h3>

F = Eq

where;

E is electric field
q is the test charge

F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

8 0

2 years ago

The outer layer of cable on a cable reel is 16.2 cm from the center of the reel. The reel is initially stationary and can rotate

ahrayia [7]

Answer:

B. w=12.68rad/s

C. α=3.52rad/s^2

Explanation:

We can solve this problem by taking into account that (as in the uniformly accelerated motion)

$\theta=\omega_{0}t+\frac{1}{2}\alpha t^{2}\\\theta = \frac{s}{r}$ ( 1 )

where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.

In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have

$\theta=\frac{3.7m}{0.162m}=22.83rad$

$22.83rad=\frac{1}{2}\alpha (3.6s)^2\\\\\alpha=2\frac{(22.83rad)}{3.6^2s}=3.52\frac{rad}{s^2}$

to calculate the angular speed w we can use $\alpha=\frac{\omega _{f}-\omega _{i}}{t _{f}-t _{i}}\\\\\omega_{f}=\alpha t_{f}=(3.52\frac{rad}{s^2})(3.6)=12.68\frac{rad}{s}$