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3 years ago

Faraday's law states that voltage can be changed by moving the coil out of the magnetic field true or false

1 answer:

8 0

As per Faraday's law of induction we know that induced EMF in a conducting closed loop is equal to rate of change in flux in that loop

So here we have

$V = \frac{d\phi}{dt}$

now when we move out a coil from magnetic field then in this case there will be EMF induced in that coil as here magnetic flux is changing with time linked with the coil.

Now this induced voltage will remain constant if coil is moved out uniformly

But it will not remain constant if coil is moved out with non uniform speed

So this statement is not always true

so answer must be

FALSE

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What is the magnitude (size) and direction of the cumulative force acting on the car shown in the picture above?

mrs_skeptik [129]

Answer:

5070

Explanation:

add them up and then you get your answers 

5 0

3 years ago

Read 2 more answers

Atmospheric conditions near a mountain range are such that a cloud at an altitude of 2.00 km contains 3.20 ✕ 10^7 kg of water va

kykrilka [37]

Answer:

time required is 6.72 years

Explanation:

Given data

mass m = 3.20 ✕ 10^7 kg

height h = 2.00 km = 2 × 10^3 m

power p = 2.96 kW =2.96 × 10^3 J/s

to find out

time period

solution

we know work is mass × gravity force × height

and power is work / time

so we say that power = mass gravity force × height / time

now put all value and find time period

power = mass × gravity force × height / time

2.96 × 10^3 = 3.20 ✕ 10^7 × 9.81× 2 × 10^3 / time

time = 62.784 × 10^10 / 2.96 × 10^3

time = 21.21081081 × 10^7 sec

time = 58.91891892 × 10^3 hours

time = 6.72 years

so time required is 6.72 years

3 0

3 years ago

What is a circuit that only has one loop??

larisa86 [58]

Series :) is the answer

6 0

3 years ago

A(n) 1400-kg car going at 6.32 m/s in the positive x direction collides with a 2900-kg truck at rest. The collision is totally i

tresset_1 [31]

Answer:

a) Acceleration of the car is given as

$a_{car} = -21 m/s^2$

b) Acceleration of the truck is given as

$a_{truck} = 10.15 m/s^2$

Explanation:

As we know that there is no external force in the direction of motion of truck and car

So here we can say that the momentum of the system before and after collision must be conserved

So here we will have

$m_1v_1 + m_2v_2 = (m_1 + m_2)v$

now we have

$1400 (6.32) + 2900(0) = (1400 + 2900) v$

$v = 2.06 m/s$

a) For acceleration of car we know that it is rate of change in velocity of car

so we have

$a_{car} = \frac{v_f - v_i}{t}$

$a_{car} = \frac{2.06 - 6.32}{0.203}$

$a_{car} = -21 m/s^2$

b) For acceleration of truck we will find the rate of change in velocity of the truck

so we have

$a_{truck} = \frac{v_f - v_i}{t}$

$a_{truck} = \frac{2.06 - 0}{0.203}$

$a_{truck} = 10.15 m/s^2$

5 0

3 years ago

Which explanation BEST supports Newton's second law of motion which states that force = mass x acceleration?

GaryK [48]

The answer is C. F=ma basically says that force is a function of mass multiplied by acceleration. The first two answers don’t make sense because there’s no necessary relationship between mass and acceleration. And for the last two, the higher the mass, the higher the force needed, therefore C is the correct answer.

8 0

2 years ago