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Vinil7 [7]
3 years ago
8

Charge q1 is placed a distance r0 from charge q2 . What happens to the magnitude of the force on q1 due to q2 if the distance be

tween them is reduced to r0/4 ?
Physics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

The magnitude of the force between the two charges will be increased.

Explanation:

The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled

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\\ \sf\longmapsto ∆P=P

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3 years ago
An electromagnetic wave has a frequency of 1.0 x 10^5. What is the wavelength of the wave?
SashulF [63]

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6 0
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A 40.0 kg beam is attached to a wall with a hi.nge and its far end is supported by a cable. The angle between the beam and the c
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288.51 N is  the magnitude of the force that the beam exerts on the hi.nge.

Given

Mass 0f beam = 40 Kg

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Angle between the beam and cable is = 90°

Angle between beam and the horizontal component = 31°

As the system of the beam, hi_nge and cable are in equilibrium.

The magnitude of the force that the beam exerts on the hi_nge can be calculated by -

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F = 86.62 N + 40 × 9.8 × sin 31°

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F = 288.51 N

Hence, the magnitude of the force that the beam exerts on the hi_nge is 288.51  N.

Learn more about components of forces here brainly.com/question/26446720

#SPJ1

7 0
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