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2 years ago

10

The rectangle below has an area of c^2-4x-12 square meters and a length of x+2 meters what expression represents the width of th

e rectangle

1 answer:

Korolek [52]2 years ago

5 0

Answer:

Width = $\frac{c^2 - 4x - 12 }{x+2}$

Step-by-step explanation:

All we have to do is to use the method of changing the subject. First we know that length * width is equal to area.

Area = length * width

We have the area and the length but we don't have the width. So we substitute the values we have int the equation and make the width (w) the subject.

(c^2 - 4x - 12) = (x + 2) * w

(c^2 - 4x - 12) = w(x +2)

Divide both sides by (x+2) so w can stand alone.

$\frac{c^2 - 4x - 12}{x+2} = \frac{w(x+2)}{x+2}$

w = $\frac{c^2 - 4x - 12 }{x+2}$

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2 years ago

The sum of a number and its square is 182. Find the number.

Mars2501 [29]

Answer:

13 and -14 satisfy this condition

Step-by-step explanation:

Let's represent that number as x

and the square of x is x^2

So,

x + x^2 = 182

Subtract 182 from both sides

x + x^2 - 182 = 182 - 182

x + x^2 - 182 = 0

rearrange the quadratic equation

x^2 + x -182 = 0

let's use the quadratic formula

$\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

a = 1, b = 1, c = -182

$\frac{-1+\sqrt{1^2-4*1*(-182)} }{2*1}$ or $\frac{-1-\sqrt{1^2-4*1*(-182)} }{2*1}$

$\frac{-1+\sqrt{1+728} }{2}$ or $\frac{-1-\sqrt{1+728} }{2}$

$\frac{-1+\sqrt{729} }{2}$ or $\frac{-1-\sqrt{729} }{2}$

$\frac{-1+{27} }{2}$ or $\frac{-1-{27} }{2}$

$\frac{26}{2}$ or $\frac{-28}{2}$

13 or - 14

Lets check

13 + 13^2 = 13 + 169

= 182

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3 years ago

What is the surface area of this right rectangular prism glass slab with dimensions of 20 inches by 3 inches by 12 inches?

Nata [24]

The answer would be 240 since you are only looking for surface area, which means you wouldn’t include the width

6 0

2 years ago

Read 2 more answers

Solve <br>In 2x + In 2=0

irakobra [83]

Solving $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Step-by-step explanation:

We need to solve: $ln(2x)+ln(2)=0$

Solving:

$ln(2x)+ln(2)=0$

Adding -ln(2) on both sides:

$ln(2x)+ln(2)-ln(2)=0-ln(2)$

$ln(2x)=-ln(2)$

Using logarithmic rule: if $log_a b =c\,\,then\,\, b=a^c$

So,

$2x=e^{-ln(2)}$

Simplifying:

$2x=(e^{ln(2)})^{-1}\\e^{ln(2)}=2\\2x=(2)^{-1}\\2x=\frac{1}{2} \\x=\frac{1}{2x2}\\x=\frac{1}{4}$

So, Solving $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Keywords: Logarithms

Learn more about Logarithms at:

#learnwithBrainly

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3 years ago

Find the value of x (round to the nearest tenths)<br> 3x<br> 4x

Schach [20]

Answer:

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Step-by-step explanation:

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2 years ago