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kvv77 [185]
3 years ago
15

Find the value of x at tan x = 1 a) x = 0° b) x = 180° c) x= 45° d) x=90°

Mathematics
1 answer:
rewona [7]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Hope it helps you.......

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What is the value of x?<br><br> Enter your answer in the box.
valentinak56 [21]

Answer: 39

Step-by-step explanation:

180-(39+102)

180-141

39

6 0
3 years ago
Read 2 more answers
The length of a rectangle is 4 cm less than it’s width. If the area of the rectangle is 165 cm^2. What are the dimensions of the
Monica [59]

Answer:

The dimensions are 11 cm by 15 cm

Step-by-step explanation:

Area of a rectangle = (length)(width).

Let L represent the length and W the width.

Since L = W - 4, we have

Area of rectangle = (W - 4)W = 165 cm^2.

Thus, w^2 - 4W - 165 = 0.  We can solve for W using the quadratic formula:

a = 1, b = -4 and c = -165.  Thus,

        -(-4) ± √ [ (-4)² - 4(1)(-165) ]

W = ---------------------------------------

                        2

         4 ± √ [16 + 660 ]

W = ------------------------------

                       2

         4 ± √ [ 676 ]                    4 ± 26

W = -----------------------  =   W = -------------  =  W  = 2 ± 13

                  2                                  2

Thus, W is 2 + 13 = 15.  It cannot be negative, so we discard 2 - 13 = -11.

If the width, W, is 15, then the length is 4 less, or L = 11.

The dimensions are 11 cm by 15 cm

6 0
3 years ago
I need help with this because I'm not very good at understanding this.
HACTEHA [7]

Answer:

the initial value is 2

Step-by-step explanation:

"y=mx+b" is the equation

"b" is the initial value, and there is no "b" value

4 0
3 years ago
Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

5 0
3 years ago
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Find the value of y.<br> Please help asap. I've been on this for ages.
anastassius [24]

Answer:

53.50

Step-by-step explanation:

168 is the circumference so i divided it by pi (3.14)

5 0
3 years ago
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