Answer:
True
Explanation:
In an uncompetitive inhibition, initially the substrate [S] binds to the active site of the enzyme [E] and forms an enzyme-substrate activated complex [ES].
The inhibitor molecule then binds to the enzyme- substrate complex [ES], resulting in the formation of [ESI] complex, thereby inhibiting the reaction.
This inhibition is called uncompetitive because the inhibitor does not compete with the substrate to bind on the active site of the enzyme.
Therefore, in an uncompetitive inhibition, the inhibitor molecule can not bind on the active site of the enzyme directly. The inhibitor can only bind to the enzyme-substrate complex formed.
The metal is aluminium
<u>Explanation:</u>
Given:
Heat, q = 4680 J
Mass, m = 100g = 0.1kg
ΔT = 52°C
sample = ?
We know:
q = mcΔT
On substituting the value we get:
Thus, the metal is aluminium which has a specific heat capacity of 900 J/kg°C
Answer:
[H3O+] = 1.0*10^-12 M
[OH-] = 0.01 M
Explanation:
We can use the following equation to find the hydronium ion concentration. Plug in the pH and solve for H3O+.
pH = -log[H3O+]
<u>[H3O+] = 1.0*10^-12 M</u>
Now, to find the hydroxide ion concentration we will use the two following equations.
14 = pH + pOH
pOH = -log[OH-]
14 = 12 + pOH
pOH = 2
2 = -log[OH-]
<u>[OH-] = 0.01 M</u>
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Answer:
f = 1.1041 × 10¹⁵ s⁻¹
λ = 2.72 × 10⁻⁷ m
Explanation:
Given data:
Energy of photon = 7.32 × 10⁻¹⁹ J
Wavelength = ?
Frequency = ?
Solution:
Formula
E = h. f
h = planck's constant = 6.63 × 10⁻³⁴ Kg.m²/s
Now we will put the values in equation
f = E/h
Kg.m²/s² = j
f = 7.32 × 10⁻¹⁹ Kg.m²/s² / 6.63 × 10⁻³⁴ Kg.m²/s
f = 1.1041 × 10¹⁵ s⁻¹
Wavelength of photon.
E = h.c /λ
λ = h. c / E
λ = (6.63 × 10⁻³⁴ Kg.m²/s × 3 × 10⁸ m/s) / 7.32 × 10⁻¹⁹ Kg.m²/s²
λ = 19.89 × 10⁻²⁶ / 7.32 × 10⁻¹⁹ m
λ = 2.72 × 10⁻⁷ m
