4 years ago

When must you inspect your tool and extension cord

Engineering

2 answers:

mojhsa [17]4 years ago

7 0

If you suspect anything is wrong with it such as it not working or before using one of them

tamaranim1 [39]4 years ago

5 0

Just expanding on the original answer, Or a shortage of some sort or malfunction

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Consider two different types of motors. Motor A has a characteristic life of 4100 hours (based on a MTTF of 4650 hours) and a sh

Daniel [21]

Answer:B

Explanation:

Given

For motor A

Characteristic life(r)=4100 hr

MTTF=4650 hrs

shape factor(B )=0.8

For motor B

Characteristic life(r)=336 hr

MTTF=300 hr

Shape Factor (B)=3

Reliability for 100 hours

$R_a=e^{-\left ( \frac{T-r}{n}\right )B}$

$R_a=e^{-\left ( \frac{4650-4100}{100}\right )0.8}$

$R_a=e^{-4.4}=0.01227$

For B

$R_b=e^{-\left ( \frac{300-336}{100}\right )3}$

$R_b=e^{1.08}=2.944$

B is better for 100 hours

(b)For 750 hours

$R_a=e^{-0.5866}=0.55621$

$R_b=e^{0.144}=1.154$

So here B is more Reliable.

3 0

3 years ago

Carbon dating for archeological materials is based on the fact that a plant, after its death, stops absorbing radioactive C-14 a

Olin [163]

Answer:

t = 2212 years

Explanation:

In radioactive decay processes it is described by the equation

N = N₀ $e^{-\lambda t}$

to calculate the activity

$T_{1/2}$ = log 2 /λ

λ = log 2 / T_{1/2}

λ = log 2 /5715

λ = 5.267 10⁻⁵

now the amount of carbon 14 is N₀ = 0.1%, the sample contains an amount of N = 0.089%

N / N₀ = e^{-\lambda t}

-λ t = ln N / N₀

t = - 1 /λ ln N /N₀

t = 1 / 5.267 10⁻⁵ ln (0.089 / 0.1)

t = 2,212 10³ years

t = 2212 years

8 0

3 years ago

Make a list of common uses of pneumatic systems in engineering contexts. Explain how each system functions and what benefit it b

MArishka [77]

Answer:

Bicycle Pumps. These pumps are used to inflate bicycle wheels, basketballs, footballs, Ect. Brakes on Buses and Trucks. Tire Pressure Gauges. Jackhammer. Pneumatic Nail Guns.

Explanation:

8 0

2 years ago

Read 2 more answers

Theres the other one

garik1379 [7]

Answer:

3 one in last one is there

8 0

3 years ago

Read 2 more answers

14. A digital computer has a memory unit with 32 bits per word. The instruction set consists of 110 different operations. All in

Fofino [41]

Answer:

7 bits

Explanation:

Given

Instruction Set = 110 operation

Memory unit = 32 bits per word.

We get the required bits by using the following formula

2^n = 110

But 110 is not a factor of 2.

So, we pick the nearest decimal number greater than 110 that is a power of 2.

The number is 128

2^n = 110 becomes

2^n = 128

2^n = 2^7 ---- 2 cancels out

So,

n = 7

Hence, the required number of bits needed for the opcode is 7 bits

5 0

3 years ago