Answer:
a) the average length per chip is 3 mm
b) the metal removal rate MR is 90 mm³/sec
c) number of chips formed per unit time for the portion of the operation when the wheel is engaged in the work is 4,000,000 chips/min
Explanation:
Given that;
wheel diameter = 150 mm
infeed = 0.06 mm
wheel speed = 1600 m/min = 16000000 mm/s
work speed = 0.30 m/s = 300 mm/s
cross feed = 5 mm
active grits per area = 50 grits/cm²
a)
Average length per chip
Average chip length is given by
Lc = √fd
f is infeed and d is diameter of the wheel
so we substitute
Lc = √( 0.06 × 150
Lc = √ 9
Lc = 3 mm
Therefore the average length per chip is 3 mm
b)
metal removal rate MR is expressed as;
MR = fvc
v is work speed, c is cross feed and f is infeed
so we substitute
MR = 0.06 × 300 × 5
MR = 90 mm³/sec
Therefore the metal removal rate MR is 90 mm³/sec
c)
number of chips formed per unit time is expressed as
No = Vw × c × G
Vw is wheel speed and G is active grits per area
so we substitute
No = 1600000 × 5 × 50/10²
= 4,000,000 chips/min
Therefore number of chips formed per unit time for the portion of the operation when the wheel is engaged in the work is 4,000,000 chips/min
