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Hitman42 [59]
3 years ago
8

Once Joe Martin reports his concerns to senior management at corporate headquarters and requests that the Ethicana plant operati

ons be suspended until the faulty equipment, safety and operational issues are corrected it would be unethical for Joe to file a report with the Ethicana Worker Safety and Environmental Protection Agency if the plant continues in operation without repairs.
Engineering
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer: It would be unethical to file a report on safety without proper repairs.

Explanation: As a top staff in the company Joe, complained to his senior management at their headquarters about the faulty parts and unsafe working conditions at the Ethicana plant. After filing his complaint nothing is done to correct it, therefore for Joe to give a safety report for an unsafe working environment is highly unethical and is against what engineering stands for in the area of occupational health safety and environment. It is best for him to stand his ground that the faulty equipments be fixed and that the unsafe working conditions at the Ethicana operations plants be corrected for the sake of the working population there and also for the benefit of the environment.

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A rectangular steel bar, with 8" x 0.75" cross-sectional dimensions, has equal and opposite moments applied to its ends.
denpristay [2]

Answer:

Part a: The yield moment is 400 k.in.

Part b: The strain is 8.621 \times 10^{-4} in/in

Part c: The plastic moment is 600 ksi.

Explanation:

Part a:

As per bending equation

\frac{M}{I}=\frac{F}{y}

Here

  • M is the moment which is to be calculated
  • I is the moment of inertia given as

                         I=\frac{bd^3}{12}

Here

  • b is the breath given as 0.75"
  • d is the depth which is given as 8"

                     I=\frac{bd^3}{12}\\I=\frac{0.75\times 8^3}{12}\\I=32 in^4

  • y is given as

                     y=\frac{d}{2}\\y=\frac{8}{2}\\y=4"\\

  • Force is 50 ksi

\frac{M_y}{I}=\frac{F_y}{y}\\M_y=\frac{F_y}{y}{I}\\M_y=\frac{50}{4}{32}\\M_y=400 k. in

The yield moment is 400 k.in.

Part b:

The strain is given as

Strain=\frac{Stress}{Elastic Modulus}

The stress at the station 2" down from the top is estimated by ratio of triangles as

                        F_{2"}=\frac{F_y}{y}\times 2"\\F_{2"}=\frac{50 ksi}{4"}\times 2"\\F_{2"}=25 ksi

Now the steel has the elastic modulus of E=29000 ksi

Strain=\frac{Stress}{Elastic Modulus}\\Strain=\frac{F_{2"}}{E}\\Strain=\frac{25}{29000}\\Strain=8.621 \times 10^{-4} in/in

So the strain is 8.621 \times 10^{-4} in/in

Part c:

For a rectangular shape the shape factor is given as 1.5.

Now the plastic moment is given as

shape\, factor=\frac{Plastic\, Moment}{Yield\, Moment}\\{Plastic\, Moment}=shape\, factor\times {Yield\, Moment}\\{Plastic\, Moment}=1.5\times400 ksi\\{Plastic\, Moment}=600 ksi

The plastic moment is 600 ksi.

3 0
3 years ago
If the slotted arm rotates counterclockwise with a constant angular velocity of thetadot = 2rad/s, determine the magnitudes of t
astraxan [27]

Answer:

Magnitude of velocity=10.67 m/s

Magnitude of acceleration=24.62 ft/s^{2}

Explanation:

The solution of the problem is given in the attachments

3 0
3 years ago
An 80-percent-efficient pump with a power input of 20 hp is pumping water from a lake to a nearby pool at a speed of 10 ft/s thr
Sladkaya [172]

Answer:

Part A

The mass plow rate, is approximately 97.0 lbm/s

Part B

The power used to overcome friction, is approximately 1.9 hp

Explanation:

The efficiency of the pump, η = 80%

The power input to the pump, P = 20 hp

The speed of the water through the pipe, v = 10 ft./s

The diameter of the pipe, d = 5.2 inches = 13/30 ft.

The free surface of the pool above the lake, h = 80 ft.

The density of the water, ρ = 62.4 lbm/ft.³

Part A

The mass plow rate, \dot m = Q × ρ

Where;

ρ = 62.4 lbm/ft³

Q = A × v

A = The cross-sectional area of the pipe

∴ Q = π·d²/4 × v = π × ((13/30 ft.)²)/4 × 10 ft.s ≈ 1.4748 ft.³/s

∴ The mass plow rate, \dot m ≈ 1.4748 ft.³/s × 62.4 lbm/ft.³ = 97.02752 lbm/s

The mass plow rate, \dot m ≈ 97.0 lbm/s

Part B

The power to pump the water at the given rate, P_w =  \dot m·g·h

∴ P_w =  97.02752 lbm/s × 32.1740 ft./s² × 80 ft. ≈ 14.1130725 Hp

P_w ≈ 14.1130725 Hp

The power output of the pump, P_{out} = 0.8 × 20 hp = 16 hp

Therefore, the power used to overcome friction, P_f = P_{out} - P_w

∴ P_f ≈ 16 hp - 14.1130725 Hp ≈ 1.8869275 hp

The power used to overcome friction,  P_f ≈ 1.9 hp

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3 years ago
Any programmer who writes a Diophantine equation solver must occasionally encounter an infinite loop.
Sergio [31]

Answer: True

Explanation:

An Infinite loop occurs in a computer programming when a sequence of instructions run endlessly without stopping until there is an external intervention, this intervention could be pull or plug. It is also known as endless loop. It occurs due to using of variables that are not properly updated or when there is an error in looping condition.

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4 years ago
It is required to design and implement: 1. A counter which counts from 0 to 255 with seven segment display.
liubo4ka [24]

Answer:

A counter which counts from 0 to 255 with seven segment display

Timer Mode Control (TMOD)

Explanation:

5 0
3 years ago
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