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Hitman42 [59]
3 years ago
8

Once Joe Martin reports his concerns to senior management at corporate headquarters and requests that the Ethicana plant operati

ons be suspended until the faulty equipment, safety and operational issues are corrected it would be unethical for Joe to file a report with the Ethicana Worker Safety and Environmental Protection Agency if the plant continues in operation without repairs.
Engineering
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer: It would be unethical to file a report on safety without proper repairs.

Explanation: As a top staff in the company Joe, complained to his senior management at their headquarters about the faulty parts and unsafe working conditions at the Ethicana plant. After filing his complaint nothing is done to correct it, therefore for Joe to give a safety report for an unsafe working environment is highly unethical and is against what engineering stands for in the area of occupational health safety and environment. It is best for him to stand his ground that the faulty equipments be fixed and that the unsafe working conditions at the Ethicana operations plants be corrected for the sake of the working population there and also for the benefit of the environment.

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Explanation:

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Using the AASHTO 1993 Flexible Pavement Design Procedure, design a pavement cross section that will provide 10 years service. Th
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Answer:

Check the explanation

Explanation:

Single Unit Truck ESAL = 43.38 + 5.16 = 48.54

Semi Unit Truck ESAL = 43.38+ 6.00+7.4 = 56.78

So total ESAL's during design life = (400*48.54 + 350*56.78)*365*10/18000 = (19416+19873)*3650= 3939

Kindly check the attached image

Here

Reliability = 95% = 0.95, therefore ZR = -1.645, S0 = 0.4, MR = 18

Delta PSI = 4.2-2.5= 1.7

Resilient Modulus = 18000 psi, So MR = 18

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There W18 calculates to 0.26807

So

log10 (3939) = 9.36*log10(SN+1) -.2/(.4+1094/(SN+1)5.19)) -6.01

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= a1*d1 + a2*d2 +a2*d3

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3 years ago
The equilibrium fraction of lattice sites that are vacant in silver (Ag) at 700°C is 2 × 10-6. Calculate the number of vacancies
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1.16*10^{23} vacancies/m^3

Explanation:

Data given

temperature =700c

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N=\frac{p_{Ag} * N_A}{A_{AG}} \\N=\frac{6.022*10^{23} * 10.35*10^6g/m}{107.87g/mol} \\N=5.78*10^{28}atom/m^3

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N_v=2*10^{-6} *5.78*10^28\\N_v=1.16*10^{23} vacancies/m^3

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