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Vinvika [58]
3 years ago
14

Q.13 In order to produce maximum starting torque in a split-phase motor, how many degrees out of phase should the start- and run

-winding currents be with each other?
Select one:
A. 180°
B. 0°
C. 120°
D. 90°
Engineering
1 answer:
Phantasy [73]3 years ago
3 0

Answer:

D. 90 degrees.

Explanation:

Torque is a rotational force which moves an object in other direction. There should be 90 degrees out of phase to start, run winding currents with each other. Torque is produced by the rotational motion of an object. The angle of the object must be 90 degrees set in order to create torque.

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I want a problems and there solutions of The inception of cavitation?​
Ugo [173]

Answer:

The overview of the given scenario is explained in explanation segment below.

Explanation:

  • The inception of cavitation, that further sets the restriction for high-pressure and high-free operation, has always been the matter of substantial experimental study over the last few generations.
  • Cavitation inception would be expected to vary on the segment where the local "PL" pressure mostly on segment keeps falling to that are below the "Pv" vapor pressure of the fluid and therefore could be anticipated from either the apportionment of the pressure.

    ⇒  A cavitation number is denoted by "σ" .

4 0
3 years ago
trình bày những hiểu biết cơ bản nhất về thiết bị máy chụp X-quang trong môn học trang bị điện thiết bị y tế? trên cơ sở môn học
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Answer:

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8 0
3 years ago
A company specification calls for a steel component to have a minimum tensile strength of 1240 MPa. Tension tests are conducted
polet [3.4K]

Answer:

HV = 372.4 KGf/mm^2

HR_C = 39.445

Explanation:

given data:

minimum tensile strength = 1240 MPa

we knwo that \sigma_{vrs}  and brinell hardness number (HB} relation given as

\sigma_{vrs} = 3.4 \times H.B

H.B = \frac{1240}{3.4} = 364.7

1) relation betwen H.B and Rockwell is

 HR_C = 6.96 + 0.089 HB

 HR_C = 6.96 + (0.089\times 365} = 39.445

2) relation between HB  and Vickers hardnes HV is given as

 HB \times 1.05 = HV + 10.5

HV = HB\times 1.05 - 10.5

HV = 372.4 KGf/mm^2

4 0
4 years ago
The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that deliv
Debora [2.8K]

Answer:

Tmax = 2.934ksi

φ = 4.58°

Explanation:

Given.

Length = 100 ft

Maximum power = 2590 hp

Angular rotate = 1700 rpm .

Outer diameter of the shaft = 8 in. Wall thickness = 3/8 in.

Calculating angular velocity.

= 1700rev/min * 2πrad/rev * 1min/60s

= 56.67πrad/s

Convert power to ft.lb/s

2590hp = 2590 * 550

= 1424500ft.lb/s

At this point, we calculate torque.

Torque = Power/Angular Velocity

Torque = 1424500/56.67π

Torque = 8000.24lb.ft

Using the torsion formula, we'll calculate maximum stress due to the shear force acting on the body:

Tmax = ½(Tc/J)

Tmax =½ of (8001.24 * 12 * 4 )/ (π/4)(4⁴ - 3.625⁴)

Tmax = ½ * 5868.656298363693

Tmax = 2934.328149181846

Tmax = 2.934ksi

Calculating the angle twist

φ = TL/JG

φ = (8001.24 * 12 * 100 * 12 )/( (π/4)(4⁴ - 3.625⁴)(4⁴ - 3.625⁴)(11)(10^6))

φ = 0.08002 rad -- convert to degrees

φ = 4.58° --- approximated

8 0
3 years ago
What is a build enviroment in construction
Elden [556K]

Answer: Cultural Issues and the Human-Made Environment. Mass production and related machine techniques in construction and servicing also dictate a multitude.

Explanation:

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3 years ago
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