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Hunter-Best [27]

3 years ago

9

juan said that the two shapes below are quadrilaterals is he correct? the shapes are like a slanted short rectangle and like a s

mall bowl but looks like a cup

1 answer:

Helen [10]3 years ago

8 0

He is wrong none of them is a quadrilateral

You might be interested in

How do I solve <br><br> x² - 10x-3=0

evablogger [386]

Answer:

x = 5±2√7

Step-by-step explanation:

This quadratic cannot be factorised via the factorisation method, so we use the quadratic formula :

x = $\frac{-b + \sqrt{b^{2} -4ac} }{2a}$ or x = $\frac{-b - \sqrt{b^{2} -4ac} }{2a}$

(The reason I did 2 equations is because brainliest does not allow me to do the ± in the equation insert thing )

x = $\frac{-(-10) + \sqrt{-10^{2} -4(1)(-3)} }{2(1)}$ or x = $\frac{-(-10) - \sqrt{-10^{2} -4(1)(-3)} }{2(1)}$

x = $\frac{10 + \sqrt{100+12} }{2}$ or x= $\frac{10 - \sqrt{100+12} }{2}$

x = $\frac{10 + {4\sqrt{7}} }{2}$ or x = $\frac{10 - {4\sqrt{7}} }{2}$

x = $5+2\sqrt{7}$ or x = $5 -2\sqrt{7}$

Hope this helped and brainliest please

3 0

2 years ago

Solve this equation: 2s + s + 12 = 132.<br> a. s = 9<br> B. s = –30<br> C. s = 120<br> D. s = 40

madam [21]

The equation given in the question is
2s + s + 12 = 132
3s + 12 = 132
3s = 132 - 12
3s = 120
s = 120/3
= 40
From the above deduction we can see that the value of the unknown variable comes out to be exactly 40. This is possible because there is a single unknown variable and a single equation to get the value of the variable from. So the correct option among all the options given in the question is option "D".

8 0

3 years ago

Read 2 more answers

A line passes through point A (14,21). A second point on the line has an x-value that is 125% of the x-value of point A and a y-

seropon [69]

Answer:

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

Step-by-step explanation:

According to the statement, let $A(x,y) = (14,21)$ and $B(x,y) = (1.25\cdot x_{A},0.75\cdot y_{A})$ . The equation of the line in point-slope form is defined by the following formula:

$y-y_{A} = m\cdot (x-x_{A})$ (1)

Where:

$x_{A}$ , $y_{A}$ - Coordinates of the point A, dimensionless.

$m$ - Slope, dimensionless.

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

In addition, the slope of the line is defined by:

$m = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}$ (2)

If we know that $x_{A} = 14$ and $y_{A} = 21$ , then the equation of the line in point-slope form is:

$x_{B} = 1.25\cdot (14)$

$x_{B} = 17.5$

$y_{B} = 0.75\cdot (21)$

$y_{B} = 15.75$

From (2):

$m = \frac{15.75-21}{17.5-14}$

$m = -\frac{3}{2}$

By (1):

$y-21 = - \frac{3}{2}\cdot (x-14)$

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

5 0

3 years ago

Two mechanics worked on a car. The first mechanic worked for

Temka [501]

Write a system of equations:

x + y = 125

20x + 15y = 2100

Solving:

x = 125 - y

20(125 - y) + 15y = 2100
2500 - 20y + 15y = 2100
2500 - 5y = 2100
-5y = 2100 - 2500
-5y = -400
y=80

x + 80 = 125
x = 125 - 80
x = 45

The first charges 45$ per hour and the second charges 80$ per hour

4 0

2 years ago

F(x) = 2x, find the ordered pair when x = 1. O (1,2) 0 (4,1) (2,1) O (1,4)

kenny6666 [7]

Answer:

The ordered pair is (1, 2) ⇒ A

Step-by-step explanation:

In the function f(x) = y

x is the domain of the function

y is the range of the function

The domain is all the x-coordinates of the points lie on the graph of the function

The range is all the y-coordinates of the points lie on the graph of the function

That means any ordered pair (x, y) satisfy the function f(x) = y, lies on the graph of the function

∵ f(x) = 2x

→ That means y = 2x

∵ x = 1

→ Substitute the value of x in the function above

∴ f(1) = 2(1)

∴ f(1) = 2

→ That means at x = 1, y = 2

∴ The ordered pair is (1, 2)

6 0

3 years ago