What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?
2 answers:
Answer:
x+2
Step-by-step explanation:
we know that
To find out the factors of a polynomial, determine the x-intercepts or zeros of the polynomial
Remember that
The x-intercepts of a polynomial are the values of x when the value of the polynomial is equal to zero
In this problem
Looking at the graph
For x=-2, f(x)=0
so
x=-2 is an x-intercept or zero of the polynomial
To find out the factor move the constant to the left side and equate to zero
adds 2 both sides
therefore
The factor is (x+2)
You might be interested in
Answer:
The image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:
- D' (0, 1)
- L' (1/2, 5/2) or L'(0.5, 2.5)
- W' (5/2, 2) or W'(2.5, 2)
`The figure of the dilated image is attached below.
Step-by-step explanation:
Given the triangle ΔDLW withe the vertices
- D(0, 2)
- L(1, 5)
- W(5, 4)
As the scale factor 1/2 < 0, thus the image triangle will be smaller than the original triangle.
The rule of dilation is given by
Dilation: (x, y) → (1/2x, 1/2y), centered at (0, 0)
D(0, 2) → D' (1/2x, 1/2y) → D' (1/2(0), 1/2(2)) = D' (0, 1)
L(1, 5) → L'(1/2x, 1/2y) → L'(1/2(1), 1/2(5)) = L' (1/2, 5/2)
W(5, 4) → W'(1/2x, 1/2y) → W'(1/2(5), 1/2(4)) = W' (5/2, 2)
Therefore, the image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:
- D' (0, 1)
- L' (1/2, 5/2) or L'(0.5, 2.5)
- W' (5/2, 2) or W'(2.5, 2)
`The figure of the dilated image is attached below.
