All categories

3 years ago

use the quadratic formula to solve the equation. If necessary, round the nearest hundredth. 2a^2-30a+108=0

1 answer:

7 0

We know that

the formula to solve the quadratic equation is
x={-b(+/-)√[b²-4ac]}/2a

we have
2a²<span>-30a+108=0
where
a=2
b=-30
c=108

</span>x={30(+/-)√[30²-4*2*108]}/(2*2)
x={30(+/-)√[36]}/(4)
x={30(+/-)6}/(4)
x1=(30+6)/4----> 36/4----> 9
x2=(30-6)/4----> 24/4----> 6

the answer is
the values of a are
a1=9
a2=6

You might be interested in

Line m and p are perpendicular. if the slope of line m is -3, what is the slope of line p

telo118 [61]

Perpendicular slopes multiply to -1, so are <em>negative reciprocals.</em>

-1 / -3 = 1/3

Answer: B. 1/3

6 0

4 years ago

ASAP PLEASEEEEEEEE

shtirl [24]

Answer:

x = -122/13 OR 9.3846

Step-by-step explanation:

First, take a look at the second equation. Add 8x to the other side.

-7y= 8x -18

Then, divide by -7 to get a regular "y=" equation.

y= 8/7x -18/7

Move on the the first equation. Let's get "y" by itself. Add 3x to the other side.

y= 3x +15

Considering both equations are equal to Y, set them equal ( except the "y" part )

8/7x - 18/7 = 3x + 15

Multiply all by seven so that there are no fractions.

8x - 18 = 21x + 105

Subtract 8x from both sides.

-17 = 13x + 105

Subtract 105 from both sides.

-122 = 13x

Divide by 13 on both sides.

x = 9.3846

Or if you don't want decimals, just say x = -122/13

Quick Note: I made a mistake. I had looked at the second equation at -18. The answer is incorrect but the method of solving is correct. Also, make sure to plug in the value of x to get Y.

5 0

3 years ago

What are the values of the variables in the triangle below?

harkovskaia [24]

Answer:

D) x=9 ; y=3√(3)

Step-by-step explanation:

$Sin(30)=\cfrac{y}{6\sqrt{3} }$

$\cfrac{18y}{6\sqrt{3}}=18\sin \left(30^{\circ \:}\right)$

$\sqrt{3}y=9$

$\cfrac{\sqrt{3}y}{\sqrt{3}}=\cfrac{9}{\sqrt{3}}$

$y=3\sqrt{3}$

$Cos(30)=\cfrac{x}{6\sqrt{3} }$

$\cfrac{18x}{6\sqrt{3}}=18\cos \left(30^{\circ \:}\right)$

$\sqrt{3}x=9\sqrt{3}$

$\cfrac{\sqrt{3}x}{\sqrt{3}}=\cfrac{9\sqrt{3}}{\sqrt{3}}$

$x=9$

Therefore, x=9 and y=3√(3)

8 0

2 years ago

Ira Lisetskai [31]

answer = ) 100.80

Step-by-step explanation:

I subtracted the people who payed on the 1st of the month which was 4 from the total 12 memebers. I got 8, then that 8 payed on the 2nd of the month so I multiplied 8 by 12.60

5 0

2 years ago

Solve and explain please

Makovka662 [10]

Answer:

Angle A is 64 degrees

Step-by-step explanation:

See attachment

5 0

3 years ago