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natima [27]
3 years ago
5

Find the final temperature of water given an initial temperature of 28 °C, a mass of 5 kg, heat (q) of 184 J. (Specific Heat of

water = 4.184). a. 19.2°C b. 36.8 °C c. 38.8 °C d. 3880 °C
Chemistry
1 answer:
guapka [62]3 years ago
6 0

Explanation:

Initial temp = 28 °C

Final Temp = ?

Heat = 184 J

mass = 5 g

c = 4.184 joule/gram °C

The relationship between these parameters is given by the equation;

H = mCΔT

ΔT = H / mC

ΔT = 184 / 5(4.184)

ΔT = 184 / 20.92

ΔT = 8.8 °C

ΔT = Final Temp - Initial Temp

Final Temp = Initial Temp + ΔT

Final Temp = 28°C  + 8.8 °C

Final Temp = 36.8°C

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yawa3891 [41]

Answer:

The organisms that eat the producers are the primary consumers. They tend to be small in size and there are many of them. ... Because of this inefficiency, there is only enough food for a few top level consumers, but there is lots of food for herbivores lower down on the food chain.

Explanation:

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3 years ago
why do chemist use relative masses of atoms compared to a refference isotope rather than the actual of the atoms
Maksim231197 [3]

It's as simple as the actual masses of atoms are very small and difficult to work with, that's all.

To expand...

I think logically, it would make sense to use the mass of the individual atoms as your result would be more precise or "true", but practically it would be extraordinarily hard to do.  

Relative atomic masses are compared to the Carbon-12 isotope and averaged which is important. The values have been averaged and so in calculations the difference between using relative atomic mass and the actual masses of the atoms will be small. Relative atomic mass accounts for not knowing the mass all atoms as your relative atomic mass is the average mass of the isotopes in a naturally occurring sample of the element, taking into account the proportion of each isotope present.

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3 years ago
50.00 mL of a solution containing 0.15 M CH2 (CO2 H)2 and 0.020 M MnSO4
sveta [45]

Answer:

m_{solute}=0.78gCH_2 (CO_2 H)_2

Explanation:

Hello.

In this case, for the given volume and molarity of malonic acid (solute), we can compute the mass by first computing the moles considering the definition of molarity:

M=\frac{n_{solute}}{V_{solution}} \\\\n_{solute}=M*V_{solution}=0.15mol/L*50.00mL*\frac{1L}{1000mL}\\ \\n_{solute}=0.0075molCH_2 (CO_2 H)_2

Then, since the molar mass of the malonic acid is 104.1 g/mol, we can compute the required mass in g of malonic acid for the preparation of that solution as shown below:

m_{solute}=0.0075molCH_2 (CO_2 H)_2*\frac{104.1gCH_2 (CO_2 H)_2}{1molCH_2 (CO_2 H)_2}\\ \\m_{solute}=0.78gCH_2 (CO_2 H)_2

Notice that the shortest number is the molarity (0.15 M) with two significant figures, that is why the answer is displayed with two significant figures too.

Regards.

6 0
4 years ago
Balance this equation _Al +_HCl --> _H2 +_AlCl3
ivanzaharov [21]

Answer:

A²I⁴H²2C²3.............

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3 years ago
Why in a stream containing water, the mole fraction of a given
Rashid [163]

Answer:

A liquid, at any temperature, is in equilibrium with its own steam. This means that on the surface of the liquid or solid substance, there are gaseous molecules of this substance. These molecules exert a pressure on the liquid phase, a pressure known as vapor pressure.

In chemistry, when we talk about dry basis, we talk about a state in which the presence of water in a gaseous state is denied for the calculation. So vapor pressure equals zero.

When we talk about the wet basis, the presence of water in the steam is considered for the calculation, which normally is expressed as a percentage or moisture.

In summary, for a gas mixture steam:

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So, in wet basis we have an extra component (water).

Assuming we only have 2 components in our steam, and being X the molar fraction of eact component:

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For dry basis the mole fraction of A it is obtained by subtracting the molar fraction of B from one. And for wet basis, we have to substract the molar fraction of B <u>AND </u>the molar fraction of water vapor. So, logically, the mole fraction Xa will be less for wet basis.

6 0
3 years ago
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