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leva [86]
3 years ago
15

An iron ore was found to contain 92.0% pyrite (fool's gold). Pyrite has the formula FeS2and is 46.5% iron. How many grams of iro

n are there in 50.8 grams of iron ore?
Chemistry
1 answer:
Liula [17]3 years ago
4 0
Firstly calculate the grams in the last 8 percent before moving onto the pyrite section.
50.8x0.08=4.064g
We know that iron ore in this case has 92 percent pyrite which contains 46.5 percent iron so we do 50.8x0.92=46.736g from this we need to find 46.5 percent of the iron content in the 92 percent pyrite section then add this answer to the 8 percent of iron ore we found at the start.46.736x0.465=21.73224g
21.73224g+4.064=25.79624g of iron ore 25.8g(3sf)
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Explanation:

# of moles = mass/molar mass

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Look at the chemical equation shown below. A, B, X, and Y represent different elements or polyatomic ions.
VLD [36.1K]

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The answer to your question is an acid base reaction

Explanation:

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3 years ago
A biologist working in a lab adds a compound to a solution that contains an enzyme and substrate. This particular compound binds
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Adding more substrate would overcome  the effect of the compound

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6 0
3 years ago
How many molecules are present in each sample?8.55 mol SO2 :molecules SO2 0.603 mol CO :molecules CO a sample of NH3 containing
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NA = 6.02×10²³

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1 mol has 6.02×10²³ molecules, therefore:

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0.603 moles of CO must have (0.603 . NA) / 1 = 3.63×10²³ molecules of monoxide

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