Answer:
Option C
Explanation:
Litmus paper shows only whether the solution is acidic or basic, but not how strong it is.
=> Base turns the red litmus paper blue
=> Acid turns the blue litmus paper red.
Answer:
Sulfite contains 3 oxygens and sulfate contains 4 oxygens
Explanation:
<span>No, xenon will not react on Nitrogen because xenon
only reacts with oxygen and fluorine. Xenon only reacts with the 2 elements
because these 2 elements contain a strong electronegative element which is high
in energy barrier that can move the electrons inside xenon elements. Xenon is an element with a symbol of Xe, it
is odorless and colorless gas. Common uses of xenon are flash lamps and arc
lamps. Xenon is a luminous element, it glows when placed near to high voltage
electric field.
</span>
Answer:
5. +5
6. +7
Explanation:
The oxidation state can be obtained as follow:
5. Oxidation state of oxygen, O = –2
Oxidation state of phosphorus, P =?
P3O10 = –5
3P + 10O = –5
3P + (10 x –2) = –5
3P – 20 = –5
Collect like terms
3P = –5 + 20
3P = 15
Divide both side by 3
P = 15/3
P = +5
Therefore, the oxidation state of P in P3O10^5- is +5
6. Oxidation state of oxygen, O = –2
Oxidation state of manganese, Mn =.?
Mn2O7 = 0
2Mn + 7O = 0
2Mn + (7 x –2) = 0
2Mn – 14 = 0
Collect like terms
2Mn = 14
Divide both side by 2
Mn = 14/2
Mn = +7
Therefore, the oxidation state of Mn in Mn2O7 is +7
<h3>
Answer:</h3>
2265 g Fe₃O₄
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O
[Given] 705.0 g H₂O
<u>Step 2: Identify Conversions</u>
[RxN] 4 mol H₂O → 1 mol Fe₃O₄
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Fe - 55.85 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol
<u>Step 3: Convert</u>
- Set up stoich:

- Multiply/Divide/Cancel units:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 4 sig figs.</em>
2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄