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Nonamiya [84]
4 years ago
5

In what type of environment would you most likely find Fish Species 1? Explain your answer.

Chemistry
2 answers:
KengaRu [80]4 years ago
5 0

Answer:

Fish are more likely to hold a soft bait longer. ... Signs of small fish activity can lead you to fishing hot spots. ... Cover can be loosely defined as anything that will hide or protect the fish.

Explanation:

Fishes live in virtually all aquatic habitats. Different species of fish are adapted for different habitats: rocky shores, coral reefs, kelp forests, rivers and streams, lakes and ponds, under sea ice, the deep sea, and other environments of fresh, salt, and brackish water.

VikaD [51]4 years ago
4 0
Most fishes live in aquatic environments such as the seas , rivers, and oceans
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The number of protoms tells you what position of the element on the periodic table is
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The theory of what an atom looks like has evolved over time. From the ancient Greeks, to Dalton, to Rutherford—no idea was exact
Nataly [62]

To being my discussion, I claim that a new atomic model should always build on an old one with the following reasons of mine. That is option B.

<h3>What is an atomic model?</h3>

An atomic model is a model that describes how the interior of an atom looks like. This first atomic model was developed by William Thomson.

To start my discussion, I claim that a new atomic model should always build on an old one with the following reasons of mine:

  • The modern scientists exploited the ideas of the ancient scientists to arrive at a better atomic model.

  • This method is proven the the works of Bohr in the Bohr atomic model which relied on quantum mechanics, built upon the Rutherford model to explain the orbits of electrons.

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2 years ago
In the emission spectrum of hydrogen the transitions observed in this experiment are in the visible region corresponding to the
Pepsi [2]

Explanation:

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda= Wavelength of radiation

R_H = Rydberg's Constant = 1.097\times 10^7m^{-1}

n_f = Higher energy level  

n_i = Lower energy level

1)  The wavelength of the n=4 to n=1.

n_i=1,n_f=4

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{1^2}-\frac{1}{4^2} \right )\\\\\lambda =9.273\times 10^{-8}m=92.73 nm

1m=10^9nm

The region of this electromagnetic transition will be in a ultraviolet region.

2) The wavelength of the n=4 to n=1.

n_i=3,n_f=4

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{4^2} \right )\\\\\lambda =1.875\times 10^{-6}m=1875 nm

1m=10^9nm

The region of this electromagnetic transition will be in an infrared region.

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3 years ago
Two protons and two neutrons are released as a result of this reaction . 222/86 Rn-&gt; 218/84 Po
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Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

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