Polynomial with real coefficients always has even number of complex roots. We know that one of them is 2 + 5i so the second one will be 2 - 5i and:
Answer B.
Not sure about the statement
movement down 5 units
move right 2 units
<h2>
Answer:</h2>
<h2>Step-by-step explanation:</h2><h3>Given:</h3>
<h3>To Find:</h3>
<h3>Solution:</h3>
We know the value of x and y,
x = 6 and y = -1 [Given]
<u>Substitute the </u><u>value,</u>
- 4x + 5y
- 4(6) + 5(-1)
- 24 + (-5)
- 24 - 5
- 19 Ans.
Answer:
(1 , 2 )
Step-by-step explanation:
Given the 2 equations
7x - y = 7 → (1)
x + 2y = 6 → (2)
Multiplying (1) by 2 and adding to (2) will eliminate the y- term
14x - 2y = 14 → (3)
Add (2) and (3) term by term to eliminate y
15x = 20 ( divide both sides by 15 )
x = = = 1
Substitute this value of x into either of the 2 equations and solve for y
Substituting in (2)
+ 2y = 6
2y = 6 - = ( divide both sides by 2 )
y = = 2