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3 years ago

The mean of five numbers is 8.

Mathematics

1 answer:

Komok [63]3 years ago

5 0

Answer:

Step-by-step explanation:

5 time 8=40

40 = total

6 times 9=54

54-40=14

I hope this will help

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Solve the following inequality. 45 < 9(x + 3) < 153 A. 8 < x < 14 B. 2 < x < 20 C. 8 < x < 20 D. 2 <

kaheart [24]

Answer:

Step-by-step explanation:

hope this help but I worked it out so it should be true

7 0

3 years ago

densk [106]

x/2 + 10 = 35 - 2x

x/2 + 2x = 35 - 10

5x/2 = 25

5x = 25.2

5x = 50

x = 50/5

x = 10

The number is 10

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3 years ago

Isaac invested $1,800 in an account paying an interest rate of 4.7%

bazaltina [42]

Answer:

$3584.86 or 3600 if rounded to the nearest 100 dollars

Step-by-step explanation:

1800(1.047)^15= 3584.86

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3 years ago

Read 2 more answers

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this question, we have that:

$\pi = 0.21$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when $M = 0.03$ . So