Ask question

Ask question

All categories

4 years ago

12

How do mountain building and volcanoes relate to plate motion at convergent boundaries

1 answer:

Lelu [443]4 years ago

7 0

The building of mountains comes from convergent boundaries, because when two plates ram into each other, it creates a mountain. It's like having 2 piles of sand. When you try and shove them together, they end up forming a hill instead of making a neat surface. Volcanoes often occur at subduction zones (look up the ring of fire (not the song ;) ) because when the plate from the ocean sinks into the mantle, the water it absorbed lowers the melting point of the rock. This makes the rock turn into magma which rises to the surface and forms volcanoes.

You might be interested in

A bowling ball with a mass of 9 kg is moving at a speed of 4 m/s. What is its

Ilia_Sergeevich [38]

I’m pretty sure it’s B

4 0

3 years ago

with what speed does a freely falling object dropped from a height of 88.2m hit the ground? how long does it take for it hit the

maria [59]

Answer:

Vf = 41.6 [m/s]

Explanation:

To solve this problem we must use the equations of kinematics.

Vf² = Vo² + (2*g*y)

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0

g = gravity acceleration = 9.81 [m/s²]

y = height = 88.2 [m]

Note: The positive sign of the equation tells us that the acceleration of gravity goes in the direction of motion.

Vf² = Vo² + (2*g*y)

Vf² = 0 + (2*9.81*88.2)

Vf = (1730.48)^0.5

Vf = 41.6 [m/s]

6 0

3 years ago

The frequency of a wavelength ?

serious [3.7K]

Answer:

$f=0.1$

Explanation:

Use the equation:

$f=\frac{1}{T}$ (where T is the period)

$f=\frac{1}{9}$ (9 comes from the period of a full wavelength)

$f=0.1$

6 0

2 years ago

A hydrogen atom has a radius of 2.5 x 10-11 m<br> Determine the radius of a magnesium atom.

baherus [9]

Answer:

$R = 1.5* 10^{-10}m$

Explanation:

Given

$r = 2.5 * 10^{-11}m$ -- radius of hydrogen atom

<em>See attachment</em>

Required

Determine the radius of magnesium atom (R)

From the attachment, the ratio of a hydrogen atom to a magnesium atom is:

$Ratio = 6mm : 36mm$

Simplify

$Ratio =1 : 6$

Represent the radius as ratio:

$Ratio = r : R$

Substitute $r = 2.5 * 10^{-11}m$

$Ratio = 2.5 * 10^{-11}m : R$

Equate both ratios

$2.5 * 10^{-11}m : R = 1 : 6$

Express as fraction

$\frac{2.5 * 10^{-11}m}{R} = \frac{1}{6}$

Cross Multiply

$R * 1 = 2.5 * 10^{-11}m * 6$

$R * 1 = 2.5 * 6* 10^{-11}m$

$R * 1 = 15* 10^{-11}m$

$R = 15* 10^{-11}m$

$R = 1.5*10* 10^{-11}m$

$R = 1.5* 10^{1-11}m$

$R = 1.5* 10^{-10}m$

Hence, the radius of the magnesium atom is: $1.5* 10^{-10}m$

6 0

3 years ago

a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m f

goblinko [34]

The effort applied : 200 N

<h3>Further explanation</h3>

Equilibrium rotation

$\large {\boxed {\bold {\sum \tau = 0}}$

F₁.d₁-F₂.d₂=0

F₁.d₁=F₂.d₂

F₁=500 N

d₁=0.5 m

d₂=1.75-0.5=1.25 m

$\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N$

5 0

3 years ago