The empirical formula of the compound is NO₂
<u><em> calculation</em></u>
Step 1: find the moles of Nitrogen and oxygen using the Avogadro's law constant
That is according to Avogadro's law 1 mole = 6.02 x 10²³ atoms
The moles of nitrogen (N) is calculated as below
= 1 mole = 6.02 x 10²³ atoms
? moles= 1.11 x 10²² atoms
<em>by cross multiplication</em>
<em> = </em>{(1 mole x 1.11 x10²² atoms) / 6.02 x 10²³ atoms} = 0.0184 moles
moles of oxygen is calculated as below
1 mole = 6.02 x 10 ²³ atoms
? moles= 2.22 x 10²² atoms
by cross multiplication
={ (1 mole x 2.22 x 10²² atoms) / 6.02 x 10²³} = 0.0369 moles
Step 2: find the mole ratio of N to O by dividing each mole by smallest number of mole (0.0184)
That is;
for N = 0.0184 /0.0184 = 1
for O =0.0369/0.0184 =2
Therefore the empirical formula = NO₂
