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3 years ago

CaCl2 + Na2CO3 → CaCO3 + 2 NaCl

Chemistry

2 answers:

alukav5142 [94]3 years ago

4 0

Answer:

8.45 moles

Explanation:

The balanced equation for the reaction is given below:

CaCl2 + Na2CO3 → CaCO3 + 2NaCl

From the balanced equation above,

1 mole of calcium chloride (CaCl2) produced 1 mole of calcium carbonate (CaCO3).

Therefore, 8.45 moles of calcium chloride (CaCl2) will also produce 8.45 moles of calcium carbonate (CaCO3)

From the illustration above, 8.45 moles of calcium carbonate (CaCO3) are produced.

Nana76 [90]3 years ago

3 0

Answer:

8.45 moles are produced

Explanation:

CaCl₂ + Na₂CO₃ → CaCO₃ + 2 NaCl

From the equation, we can see that for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl

to calculate how many moles of CaCO₃ ,we simply multiply multiply each by the 8.45 moles of CaCl₂ which will reacts

these is because for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl

therefore we have every 1x8.45(8.45) mole of CaCl₂ and 1x8.45(8.45) mole Na₂CO₃ will give 1x8.45(8.45) mole of CaCO₃ and 2x8.45(16.9) moles of NaCl

8.45 moles are produced in the reaction

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<em>Hope This Helps!</em>

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2 years ago

• We obtained the above 10.00-mL solution by diluting a stock solution using a 1.00-mL aliquot and placing it into a 25.00-mL vo

garik1379 [7]

Answer:

a) The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) 0.0035 mole

c) 0.166 M

Explanation:

Phosphoric acid is tripotic because it has 3 acidic hydrogen atom surrounding it.

The equation of the reaction is expressed as:

$H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O$

1 mole 3 mole

The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) if 10.00 mL of a phosphoric acid solution required the addition of 17.50 mL of a 0.200 M NaOH(aq) to reach the endpoint; Then the molarity of the solution is calculated as follows

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10 ml 17.50 ml

(x) M 0.200 M

Molarity = $\frac{0.2*17.5}{1000}$