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allsm [11]
3 years ago
7

CaCl2 + Na2CO3 → CaCO3 + 2 NaCl

Chemistry
2 answers:
alukav5142 [94]3 years ago
4 0

Answer:

8.45 moles

Explanation:

The balanced equation for the reaction is given below:

CaCl2 + Na2CO3 → CaCO3 + 2NaCl

From the balanced equation above,

1 mole of calcium chloride (CaCl2) produced 1 mole of calcium carbonate (CaCO3).

Therefore, 8.45 moles of calcium chloride (CaCl2) will also produce 8.45 moles of calcium carbonate (CaCO3)

From the illustration above, 8.45 moles of calcium carbonate (CaCO3) are produced.

Nana76 [90]3 years ago
3 0

Answer:

8.45 moles are produced

Explanation:

CaCl₂ + Na₂CO₃ → CaCO₃ + 2 NaCl

From the equation, we can see that for every 1 mole of CaCl₂  and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl

to calculate how many moles of CaCO₃ ,we simply multiply multiply each by the 8.45 moles of CaCl₂ which will reacts

these is because for every 1 mole of CaCl₂  and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl

therefore we have every 1x8.45(8.45)  mole of CaCl₂  and 1x8.45(8.45) mole Na₂CO₃ will give 1x8.45(8.45) mole of CaCO₃ and 2x8.45(16.9) moles of NaCl

8.45 moles are produced in the reaction

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the compressor exerts a pressure of 400 Pa to compress nitrogen gas from 3 L to 1 L. If no heat transfer occurs, how much will t
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0.79014 J

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The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

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When heated a sample consisting of only CaCO3 and MgCO3 yields a mixture of CaO and Mgo. If the weight of the combined oxides is
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Answer:

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Explanation:

where Moles of CaCO3 is equals to x and MgCO3 is y we have that...

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MgCO3 molar mass = 84.31 g / mol  = 84.31 y

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= 100 - 38.83  

=   61.17 %  

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