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3 years ago

CaCl2 + Na2CO3 → CaCO3 + 2 NaCl

Chemistry

2 answers:

alukav5142 [94]3 years ago

4 0

Answer:

8.45 moles

Explanation:

The balanced equation for the reaction is given below:

CaCl2 + Na2CO3 → CaCO3 + 2NaCl

From the balanced equation above,

1 mole of calcium chloride (CaCl2) produced 1 mole of calcium carbonate (CaCO3).

Therefore, 8.45 moles of calcium chloride (CaCl2) will also produce 8.45 moles of calcium carbonate (CaCO3)

From the illustration above, 8.45 moles of calcium carbonate (CaCO3) are produced.

Nana76 [90]3 years ago

3 0

Answer:

8.45 moles are produced

Explanation:

CaCl₂ + Na₂CO₃ → CaCO₃ + 2 NaCl

From the equation, we can see that for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl

to calculate how many moles of CaCO₃ ,we simply multiply multiply each by the 8.45 moles of CaCl₂ which will reacts

these is because for every 1 mole of CaCl₂ and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl

therefore we have every 1x8.45(8.45) mole of CaCl₂ and 1x8.45(8.45) mole Na₂CO₃ will give 1x8.45(8.45) mole of CaCO₃ and 2x8.45(16.9) moles of NaCl

8.45 moles are produced in the reaction

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Thermodynamics and Q<br> How much energy is needed to heat 40.5g of water from 15.6°C to 73.0°C

Katyanochek1 [597]

Answer:

9717.246 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of water = 40.5 g

Initial temperature (T₁) = 15.6 °C

Final temperature (T₂) = 73 °C

Specific heat capacity (C) of water = 4.18 J/gºC

Heat (Q) =.?

Next, we shall determine the change in the temperature of water. This can be obtained as follow:

Initial temperature (T₁) = 15.6 °C

Final temperature (T₂) = 73 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 73 – 15.6

ΔT = 57.4 °C

Finally, we shall determine the heat energy required. This can be obtained as follow:

Mass (m) of water = 40.5 g

Specific heat capacity (C) of water = 4.18 J/gºC

Change in temperature (ΔT) = 57.4 °C

Heat (Q) =.?

Q = MCΔT

Q = 40.5 × 4.18 × 57.4

Q = 9717.246 J

Thus, the heat energy required is 9717.246 J

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3 years ago

The reation between sulfur dioxide and oxygen is a dynamic equilibrium. what happens when the pressure of the system is

ZanzabumX [31]

Answer:

In the above reaction, sulfur dioxide and oxygen react together to form sulfur trioxide. This means that an increase in pressure would move the equilibrium to the right and result in more sulfur trioxide being formed. Pressure can only affect the position of equilibrium if there is a change in the total gas volume.

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3 years ago

During photosynthesis, sunlight shining on a plant is absorbed. Through several chemical reactions, the plant produces sugar, a

konstantin123 [22]

The answer is:
B.electromagnetic energy to chemical energy
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3 years ago

Read 2 more answers

In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form

juin [17]

Answer:

The time decreases steadily

Explanation:

We know that the rate of chemical reaction is defined as how fast or slow a chemical reaction proceeds. Hence a chemical reaction is said to proceed at a faster rate if it takes a lesser time for the reaction to get to completion.

There are certain factors that affects the rate of reaction, prominent among them is the concentration of reactants. Concentration simply means the amount of substance in a system.

Taking a look at the table given in the question, we will realize that the volume of HCl remained constant, the volume of thiosulphate increased steadily while the volume of water decreased steadily. Remember that concentration increases when less water is added to the system. This implies that the reactant concentration increases steadily. Hence, according to the collision theory, particles collide more frequently and the rate of reaction increases.

As the rate of reaction increases, it now takes a lesser time for the reaction to get to completion (indicated by the disappearance of the cross). Hence as we move down the table, it takes lesser and lesser time for the cross to disappear. This means that the column for time will decrease steadily.

3 0

3 years ago

Using the following thermochemical data: 2Y(s) + 6HF(g) → 2YF3(s) + 3H2(g) ΔH° = –1811.0 kJ/mol 2Y(s) + 6HCl(g) → 2YCl3(s) + 3H2

Luba_88 [7]

Answer:

ΔH° = 182.4 kJ/mol

Explanation:

The ΔH wanted is for the reaction :

YF3(s) + 3HCl(g) → YCl3(s) + 3HF(g)

This is a Hess Law problem where e will have to algebraically manipulate the first and second equations , add them together, and arrive at the desired equation above.

Notice if we reverse the first equation and divide it by 2 and add to the the second only divided by two, we will arrive to the desired equation:

2YF3(s) + 3H2(g) → 2Y(s) + 6HF(g) ΔH° = 1811.0 kJ/mol (change sign)

dividing by two :

YF3(s) + 3/2H2(g) → Y(s) + 3HF(g) ΔH° = 905.5 kJ/mol Eq 1

2Y(s) + 6HCl(g) → 2YCl3(s) + 3H2(g) ΔH° = –1446.2 kJ/mol

dividing this one by two,

Y(s) + 3HCl(g) → YCl3(s) + 3/2 H2(g) ΔH° = –1446.2 kJ/mol/2 = - 723.10 kJ/mol Eq 2

Now adding 1 and 2

YF3(s) + 3/2H2(g) → Y(s) + 3HF(g) ΔH° = 905.5 kJ/mol Eq 1

Y(s) + 3HCl(g) → YCl3(s) + 3/2 H2(g) ΔH° = –1446.2 kJ/mol/2 = - 723.10 kJ/mol Eq 2

________________________________________________________

YF3(s) + 3HCl(g) → YCl3(s) + 3HF(g). ΔH° = 905.5 + (-723.1) kJ/mol

ΔH° = 182.4 kJ/mol

Notice how the Y(s) and H2 cancel nicely and the coefficients are the right ones.

8 0

4 years ago