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Alex
3 years ago
5

What is the molarity of 50.84 g of Na2CO3 dissolved in 0.400 L solution?

Chemistry
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

1.20 M

Explanation:

Convert grams of Na₂CO₃ to moles.  (50.84 g)/(105.99 g/mol) = 0.4797 mol

Molarity is (moles of solute)/(liters of solvent) = (0.4797 mol)/(0.400 L) = 1.20 M

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The chemical equation shows how ammonia reacts with sulfuric acid to produce ammonium sulfate. 2NH3(aq) + H2SO4(aq) (NH4)2SO4(aq
Katena32 [7]

Answer:

7923.6 g of (NH₄)₂SO₄ can be produced by this reaction

Explanation:

The reaction is:

2NH₃ (aq) + H₂SO₄(aq)  → (NH₄)₂SO₄(aq)

In this reaction ratio is 1:1.

As the ammonia is in excess, the limiting reagent is the sulfuric acid.

So 1 mol of sulfuric can produce 1 mol of sulfate

Then, 60 moles of sulfuric must produce 60 moles of sulfate.

We convert the moles to mass:

60 mol . 132.06 g / 1mol = 7923.6 g

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