The rovibrational transition of^1H^35Cl with v = 0 rightarrow 1, J = 11 rightarrow 10 occurs at 2757.89 cm^-1, and the transitio
n with v = 0 rightarrow 1, J = 10 rightarrow 9 occurs at 2779.07 cm^-1. From this information,
i) calculate the spring constant of the vibrational potential (assuming the harmonic approximation and rigid rotor approximation) and
ii) the equilibrium length of the HCl bond.
i) calculate the spring constant of the vibrational potential (assuming the harmonic approximation and rigid rotor approximation) and
ii) the equilibrium length of the HCl bond.
1 answer:
You might be interested in
Answer:
B and C
Explanation:
When we have to do a buffer solution we always have to choose the reaction that has the <u>pKa closer to the desired pH value</u>. When we find the pKa values we will obtain:
The closer value is pKa2 with a value of 7.2. Therefore we have to use the second reaction. In which is the <u>acid</u> and
is the <u>base</u>. Therefore the answer for the first question is B and the answer for the second question is C.