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Lina20 [59]
3 years ago
5

I did this problem and I was told I did it wrong how do I fix it??

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

  (1/8)(cos(4x) -4cos(2x) +3)

Step-by-step explanation:

Your answer is correct as far as it goes. You now need to use a power-reducing identity on the cos(2x)² term in your answer. The appropriate one is ...

  cos(x)² = (1/2)(1 +cos(2x))

In the context of this problem, using this formula gives you ...

  sin(x)⁴ = (1/4)(1 -2cos(2x) +(1/2)(1 +cos(4x))

  sin(x)⁴ = (1/8)(cos(4x) -4cos(2x) +3)

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Answer:

b because it just is

Step-by-step explanation:

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2 years ago
There are two question please help.
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7 , it’s x = 12 1/3, or in decimal form, 12.33. And at 8, it’s x = -6/11, or in decimal form, -0.54
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Write 53,278 in Expanded Form
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In the city of Manhattan, it takes about 13 Starbucks to serve every 100,000 people. As of 2019, Manhattan has
astraxan [27]

Answer:

9.207

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
I need help with this, neither of my parents can help me and i want to understand.
olga2289 [7]

Answer:

See explanation

Step-by-step explanation:

1. To rewrite the expression

(4^{\frac{2}{5}})^{\frac{1}{4}},

use exponents property

(a^m)^n=a^{m\cdot n}

So,

(4^{\frac{2}{5}})^{\frac{1}{4}}=4^{\frac{2}{5}\cdot \frac{1}{4}}=4^{\frac{2}{20}}=4^{\frac{1}{10}}

2. Why 10^{\frac{1}{3}}=\sqrt[3]{10}?

Raise both sides to 10 power:

(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10

So,

(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3

3. Simplify \dfrac{3^4}{9}

Use  the Quotient of Powers Property:

\dfrac{a^m}{a^n}=a^{m-n}

Then

\dfrac{3^4}{9}=\dfrac{3^4}{3^2}=3^{4-2}=3^2

4. Solve 4\sqrt{2}+5\sqrt{4}

First, note that \sqrt{4}=2, then

4\sqrt{2}+5\sqrt{4}=4\sqrt{2}+5\cdot 2=4\sqrt{2}+10

Number 4\sqrt{2} is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.

5. The same as option 4.

3 0
2 years ago
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