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3 years ago

Which of the following describes the function −x3 + 5?

Mathematics

1 answer:

algol133 years ago

4 0

Answer:

The correct choice is C

Step-by-step explanation:

The given function is:

$-x^3+5$

The degree of this function is odd so the function will rise at one end and fall on the other end.

Since the coefficient of the leading term is negative, the graph of the function will rise at the left and fall on the right.

The correct answer is option C.

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Please help me with this questions

viktelen [127]

Answer:

See attached

Step-by-step explanation:

The answers added on the picture

8 0

3 years ago

Limit as x approaches 9 of x^2 -81/sqrt of x - 3

Ipatiy [6.2K]

Answer:

108

Step-by-step explanation:

Limit as x approaches 9 of x^2 -81/sqrt of x - 3

First substitute x into the expression

= 9²-81/√9 - 3

= 81-81/3-3

= 0/0 (indeterminate)

Apply l'hospital rule

= lim x -> 9 d/dx(x²-81)/√x - 3

= lim x -> 9 2x/1/2√x

Substitute x = 9

= 2(9)/1/2√9

=18/1/(2(3)

=18 × 6/1

= 108

Hence the limit of the function is 108

7 0

3 years ago

Polygon ABCD is a parallelogram, and . The length of is 10 units, and the length of is 5 units. The perimeter of the parallelogr

Aliun [14]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices that can be found elsewhere:

A. rectangle; P = 26 linear units

B. square; P = 42 units2

C. parallelogram; P = 42 linear units

D. trapezoid; P = 26 linear units

The answer would be A.

3 0

3 years ago

Read 2 more answers

Triangle ABC is an isosceles triangle in which side

Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using this formula, we get

$AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5$

$BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}$

$AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5$

Now,

Perimeter of triangle ABC = AB + BC + AC

$=5+\sqrt{10}+5$

$=10+\sqrt{10}$

So, perimeter of triangle ABC is $10+\sqrt{10}$ units.

Therefore, the correct option is B.

4 0

3 years ago

Read 2 more answers

This figure shows the nose cone of a rocket used for launching satellites. The nose cone houses the satellite until the satellit

egoroff_w [7]

The formula for the volume of a cone, V, is:

V = [1/3] * π * (radius)^2 * height

Here radius = 6 feet / 2 = 3 feet

Height = 15 feet

V = [1/3] π (3 feet)^2 * 15 feet = 45π feet^3

Answer: 45π feet^3

3 0

3 years ago

Read 2 more answers