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umka2103 [35]
3 years ago
8

What would be the magnification of a specimen viewed with a compound light microscope that has an objective power of 10x and an

ocular lens power of 5x?
Biology
1 answer:
mixas84 [53]3 years ago
6 0

Answer:

Objective Lenses: Usually you will find 3 or 4 objective lenses on a microscope. They almost always consist of 4x, 10x, 40x and 100x powers. When coupled with a 10x (most common) eyepiece lens, we get total magnification of 40x (4x times 10x), 100x, 400x, and 1000x. To have good resolution at 1000x, you will need a relatively sophisticated microscope with an Abbe condenser. The shortest lens is the lowest power, the longest one is the lens with the greatest power. Lenses are color coded and if built to DIN standards are interchangeable between microscopes. The high power objective lenses are retractable (ie 40xr). This means that if they hit a slide, the end of the lens will push in (spring loaded) thereby protecting the lens and the slide. All quality microscopes have achromatic, parcentered, parfocal lenses.

Explanation:

I don't know for sure if this is correct but hopefully it is( ꈍᴗꈍ)

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In a population of plants, the allele for long stems is completely dominant over the allele for short stems. If 35% of the popul
KatRina [158]
Assumptions:
1. Equilibrium has been reached for the allele proportions
2. Absence of <span>evolutionary influences such as </span>mate choice<span>, </span>mutation<span>, </span>selection<span>, </span>genetic drift<span>, </span>gene flow<span> and </span>meiotic drive<span>.
</span>
Defining L=long stem, l=short stem, and L is dominant over l.
f(x) = frequency of allele x  (expressed as a fraction of population)
Then the Hardy-Weinberg equilibrium law applies:
p^2+2pq+q^2=1
where 
f(LL)=p^2
f(Ll)=2pq
f(ll)=q^2

Given f(ll)=0.35=q^2, we have
q=sqrt(0.35)=0.591608
p=1-q=0.408392
=>
f(Ll)
=2pq
=2*0.408392*0.591608=0.483216
= proportion of heterozygous population

Answer: percentage of heterozygous population is 48.32%
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