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Juliette [100K]
3 years ago
14

Ain___accepts electrons and becomes___

Chemistry
1 answer:
Serga [27]3 years ago
3 0

<u>Answer:</u>

<em>An atom accepts electrons and becomes an anion.</em>

<em></em>

<u>Explanation:</u>

Atomic number = number of electrons = number of protons.

Atomic number of sodium is 11

So the atom contains 11 protons and 11 electrons

To find the number of neutrons we make use of the formula  

Mass number - atomic number = number of neutrons

From the periodic table, we know mass number of sodium is 23

So number of neutron = 23 - 11 = 12.

When a sodium atom loses an electron it will have 11 positive protons and 10 negative electrons. Since 1 positive charge is more, Na becomes Na^+.

Positively charged ion is called as cation

Chlorine's atomic number is 17 so it has 17 protons and 17 electrons.

When it gains an electrons, it will have 17 positive protons and 18 negative electrons. Since 1 negative charge is more, Cl becomes Cl^-.

Negatively charged ion is called as anion.

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How many moles in 2.21 x10E24 atoms of aluminum
lisov135 [29]
<h3>Answer:</h3>

3.67 mol Al

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.21 × 10²⁴ atoms Al

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 2.21 \cdot 10^{24} \ atoms \ Al(\frac{1 \ mol \ Al}{6.022 \cdot 10^{23} \ atoms \ Al})
  2. Divide:                              \displaystyle 3.66988 \ mol \ Al

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.66988 mol Al ≈ 3.67 mol Al

7 0
3 years ago
What does the specific heat for a substance indicate?
o-na [289]

O the amount of heat required to increase the temperature of 1 gram by 1°C

Explanation:

The specific heat of a substance is the amount of heat required to increase the temperature of 1 gram of a substance by 1°C. It is an intensive property that is specific to every substance.

The unit is given as J/g⁻¹°C⁻¹ or J/g⁻¹K⁻¹

This related to the quantity of heat using the expression below:

             Q = mC∅

Q is the quantity of heat added

m is the mass

C is the specific heat

∅ is the temperature change.

Learn more:

specific heat brainly.com/question/7210400

#learnwithBrainly

7 0
3 years ago
Suppose you have a calorimeter that contains 100.0 grams of water at an initial temperature of 25*C. A salt (2.19 g, 0.020 moles
katen-ka-za [31]
ΔH=MCΔT
ΔH=100 x 4.2 x 4
ΔH=1680

ΔH per mole = ΔH ÷ moles
ΔH per mole = 1680 ÷ 0.02
<span>ΔH per mole= 84000Jmol
</span>84000 ÷ 1000 = 84KJmol

its exothermic as heat is given out into the solution 
7 0
4 years ago
Read 2 more answers
Identify this reaction <br> In pic
balu736 [363]

Answer:

Double displacement

Explanation:

5 0
3 years ago
How many atoms are in 1.4 moles of H3PO4?
sdas [7]
<h3>Answer:</h3>

8.4 × 10²³ atoms H₃PO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.4 moles H₃PO₄

[Solve] atoms H₃PO₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.4 \ mol \ H_3PO_4(\frac{6.022 \cdot 10^{23} \ atoms \ H_3PO_4}{1 \ mol \ H_3PO_4})
  2. [DA] Multiply [Cancel out units]:                                                                    \displaystyle 8.4308 \cdot 10^{23} \ atoms \ H_3PO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

8.4308 × 10²³ atoms H₃PO₄ ≈ 8.4 × 10²³ atoms H₃PO₄

3 0
3 years ago
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