There are 51 motorcycles in lot
<em><u>Solution:</u></em>
Let "x" be the number of motorcycles
Let "y" be the number of cars
<em><u>There are a total of 200 vehicles on the dealerships lot</u></em>
Therefore, we frame a equation as,
number of motorcycles + number of cars = 200
x + y = 200 ---------- eqn 1
<em><u>The detailer cleaned all the wheels which totaled to 698 wheels</u></em>
We know that,
In a car there are 4 wheels and in a motorcycle there are 2 wheels
Thus we get,
2x + 4y = 698 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
x = 200 - y -------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
2(200 - y) + 4y = 698
400 - 2y + 4y = 698
400 + 2y = 698
2y = 698 - 400
2y = 298
<h3>y = 149</h3>
<em><u>Substitute y = 149 in eqn 3</u></em>
x = 200 - 149
<h3>x = 51</h3>
Thus there are 51 motorcycles in lot