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Harrizon [31]
2 years ago
14

Order the set of number from least to greatest .

Mathematics
2 answers:
earnstyle [38]2 years ago
6 0

Answer (Please vote me Brainliest if this helps!):

The answer is D

Step-by-step explanation:

Lets start off with the square roots:

\sqrt{16} = 4

\sqrt{18} = 3\sqrt{2} = 4.24264...

Mixed fraction:

4\frac{2}{3} = 4.667

Therefore the answer is D.

mario62 [17]2 years ago
4 0

9514 1404 393

Answer:

  d. √16, 4.23_23, √18, 4 2/3

Step-by-step explanation:

There are a couple of different ways to compare these numbers. Maybe one of the most straightforward is to find the decimal equivalent, rounded to hundredths.

  4.23_23 ≈ 4.23

  4 2/3 ≈ 4.67

  √18 ≈ 4.24

  √16 = 4.00

These can be sorted least-to-greatest by putting the first number (4.23) between the last two (4.00, 4.24) and reading the new list last-to-first.

  4.00, 4.23, 4.24, 4.67   ⇔   √16, 4.23..., √18, 4 2/3

_____

<em>Additional comment</em>

Another way to work this problem is to square the numbers not under a radical. 4.23...² ≈ 17.91 and (4 2/3)² ≈ 21.78. The ordering of the squares is the same as the ordering of their square roots.

  16 < 17.91 < 18 < 21.78   ⇔   √16 < 4.23... < √18 < 4 2/3

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podryga [215]
435 inches = 36 1/4 ft.

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At a shelter 15%of the dogs are puppies. There are 60 dogs at the shelter. How many are puppies???? Will Mark BRAINLLEST
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Step-by-step explanation:

Hope this helps! Happy Trails!

8 0
3 years ago
Read 2 more answers
Can someone please help me​
astra-53 [7]

Answer:

square 20 has 44 green squares

square 21 has 45 green squares

Step-by-step explanation:

To solve the problem, we need to observe the cases, and determine/define a rule for each case (odd number of sides, or even number of sides).

For square one, we note that the centre square is shared by two diagonals, so we saved one square from the two diagonals.

The side length is 3 for square 1, 4 for square 2, and so on.

Let

n= square number (1, 2,3...)

L = side length (3,4,5...)

G1(n) = function that gives the number of green squares for square n, n=odd

G2(n) = function that gives the number of green squares for square n, n=even

side length, L=n+2   ................(1)

G1(n) = twice the side length less one, as discussed above

G1(n) = 2L-1       now substitute L=n+2

G1(n) = 2(n+2) -1    simplify

G1(n) = 2n + 3

Check:

for n=1, square 1 has 2*1+3 = 5 green squares ... checks

for n=3, square 3 has 2*3+3 = 9... checks

for n=5, square 5 has 2*5+3 = 13 ....checks

For even squares, it is even easier, because

G2(n) = 2L = 2(n+2)

check:

for n=2, square 2 has 2(2+2) = 8 green squares........checks

for n=4, square 4 has 2(4+2) = 12 green squares........checks.

Fincally, we apply our formula to n=20 and n=21

square 20 : G2(20) = 2(n+2) = 2(20+2) = 44 green quars

square 21 : G1(21) = 2n+3 = 2(21)+3 = 45 green squares

5 0
3 years ago
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Radda [10]

Answer:

60cm^2

Step-by-step explanation:

15 times 8 = 120

divided by 2  = 60

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1/4hour 1/2hour 3/4 what is the total amount of time
olasank [31]
1/4+1/2=1/4+1/2=3/4

1/2=2/4

3/4 is the answer
6 0
3 years ago
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