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RUDIKE [14]
2 years ago
7

Beau buys a 3-pound bag of trail mix for a hike. He wants to make one-ounce bags for his friends with whom he is hiking. How man

y one-ounce bags can he make?
Mathematics
2 answers:
zavuch27 [327]2 years ago
7 0
1 pound=16 ounches
3 times 16=48
48 ounces means 48 one ounce bags
alexdok [17]2 years ago
4 0
He can make 48 bags. One pound is 16 ounces, so 3*16=48.
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There is 600 Dollars

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I wanted to know if my answer is correct and if it isn't please correct it.
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Step-by-step explanation:

Use the distance formula to determine the distance between two points.

the answer will be 10

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Three years ago, Tristan bought a 30-year, 5.45%, $1,000 bond. The bond pays interest semiannually. He wants to sell the bond af
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3 years ago
The cost of 15 orange is Rs 75. How much price of 12 oranges​
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1. The price of 3 metres of cloth is Rs 79.50. Find the price of 15 metres of such cloth. Solution: It is given that. Price of 3 m of cloth = Rs 79.50. We get. Price of 1 m of cloth = 79.50/3 = Rs 26.5. So the price of 15 m of cloth = 26.5 (15) = Rs 397.50. Hence, the price of 15 m of such cloth is Rs 397.50. 2. The cost of 17 chairs is Rs 9605.

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The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a
Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = \sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}

                 = {^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}  + .......+ {^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}

                = 0.04541 + ......+0.0000002079

                = 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0
2 years ago
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