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3 years ago

A(n) _____ is a rectangle with eight selection handles that represents an object's vertical and horizontal dimensions.

Mathematics

1 answer:

Savatey [412]3 years ago

7 0

Answer:

Bounding Box

Step-by-step explanation:

A bounding box is a rectangle with eight selection handles that represents an object's vertical and horizontal dimensions.

Attached you will find the picture of a bounding box.

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Kim got a prize point for every four raffle tickets she sold. She sold 362 raffle tickets. How many prize points did she get?

Diano4ka-milaya [45]

Answer:90 1/2

Step-by-step explanation:

She sold 362 tickets

She gets prize point for every 4 tickets

3 0

3 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

4 0

3 years ago

Performance scores are collected for 10 individuals and those scores are 17 12 20 11 8 18 17 9 12 and 15. Find where X sub i rep

Elden [556K]

Step-by-step explanation:

x=10-20x567++dfggyjkkvd

3 0

2 years ago

In a booster club, 1/8 of the 128 members are men. How many male members are in the club?

Novay_Z [31]

16 or B. Because 128 divided by 8 is 16

5 0

2 years ago

Read 2 more answers

Every $4,000 spent on cable TV will reach 160 fans while every $2,750 spent on radio ad will reach 125 fans. A stadium has estab

laila [671]

Answer:

Neither of the two advertising options meet the goal.

Step-by-step explanation:

Every $4,000 spent on cable TV will reach 160 fans.

Therefore, the goal of reaching 200000 fans will be fulfilled by $\frac{4000 \times 200000}{160} = 5000000$ dollars i.e. $5 million which is greater than the budget of $3 million.

Now, every $2,750 spent on radio ads will reach 125 fans.

Therefore, the goal of reaching 200000 fans will be fulfilled by $\frac{2750 \times 200000}{125} = 4500000$ dollars i.e. $4.5 million which is again greater than the budget of $3 million.

Therefore, neither of the two advertising options meet the goal. (Answer)

8 0

2 years ago