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Mrac [35]
4 years ago
12

In the equation A=1/2bh What does each of the variables stand for

Mathematics
2 answers:
alina1380 [7]4 years ago
7 0

Answer:

A is area

B is base

H is height

Step-by-step explanation:

Gnom [1K]4 years ago
5 0
(used for area of a triangle)

Area is equal to one half of the base of the triangle multiplied by the height of the triangle.

A= area
b= base
h= height
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Adrian built a structure out of 10 congruent cubes. If each cube has a volume of 8 cu. centimeters, what is the total
Dennis_Churaev [7]

Answer:

80 because each cube has a volume of 8 and there are 10 cubes

Step-by-step explanation: 10*8=80 cubic cm

5 0
3 years ago
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

k=\frac{k}{1}.

Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have x is irrational and p\in\mathbb{Q}.

Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
4 years ago
I need help pleaseeee!!!!! I don’t understand
olganol [36]

Answer:

a. x = 5, m∠FGH = 22°

b. m∠HGI = 22°

c.  m∠FGI = 44°

Step-by-step explanation:

Since GH bisects FGI this means it divides the angle in two equal parts.

a. solving for x means equating them:

5x-3 = 6x-8 =>

5x - 6x = 3 - 8 =>

x = 5.

Both m∠FGH and m∠HGI are 5*5-3 = 22°

c. Add both angles: m∠FGH + m∠HGI = 44°

8 0
3 years ago
Witch of the functions below could possibly have created this graph? A.f(x)-x^5+2x^4-3x B.f(x)=-1/3x^4+7x^2+15 C.f(x)=1.9x^8+15x
soldi70 [24.7K]

B.f(x)=-1/3x^4+7x^2+15

Step-by-step explanation:

You can use a graph tool to graph the function a visualize the behavior.

Using a graph tool, the function,.f(x)=-1/3x^4+7x^2+15 could possibly have created the graph. See attached graph for the function.

Learn More

Graphs of polynomial function: brainly.com/question/12373761

Keywords: functions, created, graph

#LearnwithBrainly

3 0
3 years ago
Which of the following equations is equivalent to y = 2x +3?
nika2105 [10]

Answer:

y - 2x = 3

Step-by-step explanation:

y = 2x + 3

-2x -2x

y - 2x = 3

4 0
3 years ago
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