Answer:
<U= 75°
<V=65°
x=50
Step-by-step explanation:
The interior angles to a triangle always equal 180°.
Set up your equation:
180= 40+x+15+x+25
Subtract 40 from 180 to get 140. Subtract 15 from both sides. Now you have 125. Subtract the 25 from both sides. You now have 100.
Divide the 100 by 2 to find what x is because your equation is now 100=2x
x=50
v= 50+15= 65 so V is 65°
U is 50+25 so U is 75°
Answer:
A' = (6, 15)
Step-by-step explanation:
We consider the center point of dilation to be the origin (0,0)
so point A(-2, -5) to A' by scale factor N = -3 means
A' = (-2*(-3), -5*(-3)) = (6, 15)
Answer:
the long diagonal d=15.49 ( rounded to the nearest hundredth)
the shortest d=√136-120(cos 30)=5.663 ( rounded to the nearest hundredth)
Step-by-step explanation:
Area=height * base
30=h*6
h=30/6=5 cm
height=asinФ
sinФ=5/10=1/2 (Ф=30)
alternate angle=180
180-30=150 degrees
diagonal²=a^2+b^2-2abcos150
d²=10²+6²-2(10)(6)(-√3/2)
d=√136+60(√3)
the long diagonal d=15.49 ( rounded to the nearest hundredth)
the shortest d=√136-120(cos30)=5.663
Answer:
Step-by-step explanation:
we know that
The measure of central angle ABC is 
radians
so
subtends the complete circle
The area of the shaded sector is the area of a quarter circle
so
The area of a quarter circle is equal to
we have
substitute
Answer:
We want to construct a confidence interval at 99% of confidence, so then the significance level would be 
and the value of 
. And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.
And if we find the critical value in the normal standard distribution or excel and we got:
And we can use the following excel code:
"=NORM.INV(0.005,0,1)"
Step-by-step explanation:
For this case we have the following info given:
We want to construct a confidence interval at 99% of confidence, so then the significance level would be and the value of . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.
And if we find the critical value in the normal standard distribution or excel and we got:
And we can use the following excel code:
"=NORM.INV(0.005,0,1)"
