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PilotLPTM [1.2K]
3 years ago
9

4 terms for this sequence plsss i’ll give brainliest

Mathematics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

4n^{2}-4n+1

Step-by-step explanation:

hopfully this is what you were looking for

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Tallulah's family took a road trip to the Grand Canyon. Tallulah slept for the last 129 miles of the trip. If the total length o
KIM [24]

Answer:

43% of the trip

Step-by-step explanation:

1. Create an Equation

300 miles/100*x percent=129 miles <=== Make an equation so you can find the percent she slept of the trip

2. Solve

300 miles/100*x percent=129 miles

3x=129 <=== 300 divided by 100 is 3 and 3 times x is also 3x

3x/3=129/3 <=== divide by 3 from both sides

x=43

Since x is 43 that means 129 equals 43% which is how much Tallulah slept

of the trip.

3. Check

300 miles/100*43%=129 miles <=== Substitute x with 43%

3x43%=129

129=129 <=== 129 is 129 which means that the answer is correct!

Please Brainliest I am trying to level Up.

8 0
2 years ago
Please help and tell me which answer on the bottom is correct. I don't know how to do math..
Illusion [34]

Answer:

875

Step-by-step explanation:

30*15=450

30*10=300

20*5=100

12.5+12.5=25

450+300+100+25=875

I worked from bottom to top

3 0
3 years ago
Read 2 more answers
Which function has a vertex at the origin?
dlinn [17]

Answer:

  (d)  f(x) = -x²

Step-by-step explanation:

For the vertex of the quadratic function to be at the origin, both the x-term and the constant must be zero. That is, the function must be of the form ...

  f(x) = a(x -h)² +k . . . . . . . . . . vertex form; vertex at (h, k)

  f(x) = a(x -0)² +0 = ax² . . . . . vertex at the origin, (h, k) = (0, 0)

Of the offered answer choices, the only one with a vertex at the origin is ...

  f(x) = -x² . . . . . a=-1

6 0
2 years ago
Further mathematics: Find the derivative of the function x^2 y + (xy)^3 +3x=0 at (-1 , 3)​
vesna_86 [32]

Answer:

3.

Step-by-step explanation:

Implicit differentiation:

x^2 y + (xy)^3 + 3x = 0

x^2 y + x^3y^3 + 3x = 0

Using the product rule:

2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0

2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0

dy/dx(x^2 + 3y^2x^3) =  (-2xy - 3x^2y^3 - 3)

dy/dx=  (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)

At the point (-1, 3).

the derivative =  (6 - 81 - 3)/(1 -27)

= -78/-26

=  3.

8 0
2 years ago
Read 2 more answers
Help!! Hw :) i have a 78 so I NEED HELP PLS
Nataly_w [17]

Answer:

I don't see attachment

Step-by-step explanation:

3 0
3 years ago
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