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Nadya [2.5K]
3 years ago
11

50 POINTS !! PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

Mathematics
2 answers:
horsena [70]3 years ago
8 0

Answer:73mi

Step-by-step explanation:

seraphim [82]3 years ago
7 0

Answer:

73

Step-by-step explanation:

48^2 + 55^2 = 5329

square root of 5329 is 73

You might be interested in
Which is the highest value? 1/100, 1/400,1/500
NNADVOKAT [17]
1/100, 1/400, 1/500

Because the numerators are the same, we just need to compare the denominators.

100< 400< 500
⇒ 1/100 > 1/400 > 1/500

Therefore, the highest value is 1/100.

Hope this helps.


3 0
3 years ago
Read 2 more answers
I need help with all of them
lara [203]
Click on the picture! This is the explanation in accident I deleted it hope it helps!

6 0
3 years ago
Please help with math
Ivan

Answer:

B is the answer

Step-by-step explanation:

8 0
1 year ago
A motorist travels 122 km before his first stop. If he had 10% of his journey to complete at this point, how long was the total
dimaraw [331]

Answer:

233km

Step-by-step explanation:

5 0
1 year ago
A batch of 580 containers for frozen orange juice contains 8 that are defective. Two are selected, at random, without replacemen
serious [3.7K]

Answer:

a. 0.12109

b. 0.0001668

c .0.9726

d. 0.01038

e. 0.01211

f. 0.000001731

Step-by-step explanation:

Sample size = 580

Defective units = 8

Number of picks = 2

a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:

P=\frac{7}{579}=0.121

b) The probability that both are defective is given by:

P=\frac{8}{580}*\frac{7}{579}= 0.000167

c) The probability that both are acceptable is given by:

P=\frac{580-8}{580}*\frac{579-8}{579}= 0.9726

d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:

P=\frac{6}{578}}= 0.0104

e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:

P=\frac{7}{578}= 0.01211

f) The probability that all three are defective is given by:

P=\frac{8}{580}*\frac{7}{579}*\frac{6}{578} = 0.000001731

7 0
3 years ago
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