His average speed is (35m/45s) = 7/9 meters per second.
His average velocity is (30m W + 5m E) / (45s) = 25 m/s West .
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Explanation:
Answer:
r = 3.787 10¹¹ m
Explanation:
We can solve this exercise using Newton's second law, where force is the force of universal attraction and centripetal acceleration
F = ma
G m M / r² = m a
The centripetal acceleration is given by
a = v² / r
For the case of an orbit the speed circulates (velocity module is constant), let's use the relationship
v = d / t
The distance traveled Esla orbits, in a circle the distance is
d = 2 π r
Time in time to complete the orbit, called period
v = 2π r / T
Let's replace
G m M / r² = m a
G M / r² = (2π r / T)² / r
G M / r² = 4π² r / T²
G M T² = 4π² r3
r = ∛ (G M T² / 4π²)
Let's reduce the magnitudes to the SI system
T = 3.27 and (365 d / 1 y) (24 h / 1 day) (3600s / 1h)
T = 1.03 10⁸ s
Let's calculate
r = ∛[6.67 10⁻¹¹ 3.03 10³⁰ (1.03 10⁸) 2) / 4π²2]
r = ∛ (21.44 10³⁵ / 39.478)
r = ∛(0.0543087 10 36)
r = 0.3787 10¹² m
r = 3.787 10¹¹ m
Answer:
The object´s displacement vector is Δr = 8i - 6 j
Explanation:
Hi there!
The position vector is given by the following function:
r = t²i - (3t + 3) j
Let´s find the position of the object at time t1 and t2:
At t1 = 1 s:
r1 = (1)² i - (3 · (1) + 3 )j
r1 = 1 i - 6 j
At t2 = 3 s:
r2 = (3)² i - (3 · (3) + 3) j
r2 = 9 i - 12 j
The displacement is calculated as follows:
displacement = Δr = final position - initial position = r2 - r1
r2 - r1 = 9 i - 12 j - (1 i - 6 j)
r2 - r1 = 9 i - 12 j - 1 i + 6 j
r2 - r1 = 8 i - 6 j
The object´s displacement vector is Δr = 8i - 6 j
