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lubasha [3.4K]
3 years ago
13

How can we determine the angle of a resultant vector

Physics
1 answer:
klasskru [66]3 years ago
8 0

The angle of a resultant vector is given by the equation tan \theta = \frac{R_y}{R_x}

Explanation:

When we compute the resultant vector starting from 2 (or more) vectord, we add the components along the x- and y- direction of the original vectors, in order to find the component of the resultant vector along the two directions.

Let's call:

R_x the component of the resultant vector along the x-direction

R_y the component of the resultant vector along the y-direction

The magnitude of the resultant vector is then given by Pythagorean's theorem:

R=\sqrt{R_x^2+R_y^2}

While the angle can be found by taking the arctangent of the ratio between the y-component and the x-component, mathematically:

tan \theta = \frac{R_y}{R_x}

Note that this angle is measured between the resultant vector and the positive direction of the x-axis.

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

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a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it wi
Lelu [443]

a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s .The amplitude of the subsequent oscillations 48.13 cm/s

a 1.25 kilogram block is fastened to a spring with a 17.0 newtons per meter spring constant. Given that K is equal to 14 Newtons per meter and mass equals 10.5 kg. The block is then struck with a hammer by a student while it is at rest, giving it a speedo of 46.0 cm for a brief period of time. The required energy provided by the hammer, which is half mv squared, is transformed into potential energy as a result of the succeeding oscillations. This is because we know that energy is still available for consultation. So access the amplitude here from here. He will therefore be equal to and by. Consequently, the Newton's spring constant is 14 and the value is 10.5. The velocity multiplied by 0.49

Speed at X equals 0.35 into amplitude, or vice versa. At this point, the spirit will equal half of K X 1 squared plus half. Due to the fact that this is the overall energy, square is equivalent to half of a K square or an angry square. amplitude is 13 and half case 14 x one is 0.35. calculate that is equal to initial velocities of 49 squares and masses of 10.5. This will be divided in half and start at about 10.5 into the 49-square-minus-14. 13.42 into the entire square in 20.35. dividing by 10.5 and taking the square as a result. 231 6.9 Six centimeters per square second. 10.5 into 49 sq. 14. 2 into a 13.42 square entire. then subtract 10.5 from the result to get the square. So that is 48.13cm/s.

To learn more about oscillations Please click on the given link:

brainly.com/question/26146375

#SPJ4

This is incomplete question Complete Question is:

a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s . what are The amplitude of the subsequent oscillations?

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3 years ago
18. For every action, there is an equal and opposite reaction.
Andrews [41]

Answer:

Thats the third law______

3 0
4 years ago
Solar cell A produces 100 joules of energy, when a light source is shown on it for 3 minutes. Solar cell B produces 200 joules o
ella [17]

Answer: (B). Solar cell B, because it generates more power.

Explanation:

Given that,

For solar cell A

Energy = 100 Joules

Time = 3 minutes = 180 sec

Power of cell A

Power = Energy/Time

P = \dfrac{100}{180}\ Watt

P = 0.55\ Watt

For solar cell B

Energy = 200 joules

Time = 5 minutes = 300 sec

Power of cell B

Power = Energy/Time

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Hence, Solar cell B, because it generates more power.

3 0
3 years ago
Read 2 more answers
Capacitors C1 = 5.85 µF and C2 = 2.80 µF are charged as a parallel combination across a 250 V battery. The capacitors are discon
posledela

Answer:

Q1_new = 515.68 µC

Q2_new = 246.82 µC

Explanation:

Since the capacitors are charged in parallel and not in series, then both are at 250 V when they are disconnected from the battery.

Then it is only necessary to calculate the charge on each capacitor:

Q1 = 5.85 µF * 250 V = 1462.5 µC

Q2 = 2.8 µF * 250 V = 700 µC

Now, we will look at 1462.5 µC as excess negative charges on one plate, and 1462.5 µC as excess positive charges on the other plate. Now, we will use this same logic for the smaller capacitor.

When there is a connection of positive plate of C1 to the negative plate of C2, and also a connection of the negative plate of C1 to the positive plate of C2, some of these excess opposite charges will combine and cancel each other. The result is that of a net charge:

1462.5 µC - 700 µC = 762.5 µC

Thus,762.5 µC of net charge will remain in the 'new' positive and negative plates of the resulting capacitor system.

This 762.5 µC will be divided proportionately between the two capacitors.

Q1_new = 762.5 µC * (5.85/(5.85 + 2.8)) = 515.68 µC

Q2_new = 762.5 µC * (2.8/(5.85 + 2.8) = 246.82 µC

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4 years ago
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