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lubasha [3.4K]
3 years ago
13

How can we determine the angle of a resultant vector

Physics
1 answer:
klasskru [66]3 years ago
8 0

The angle of a resultant vector is given by the equation tan \theta = \frac{R_y}{R_x}

Explanation:

When we compute the resultant vector starting from 2 (or more) vectord, we add the components along the x- and y- direction of the original vectors, in order to find the component of the resultant vector along the two directions.

Let's call:

R_x the component of the resultant vector along the x-direction

R_y the component of the resultant vector along the y-direction

The magnitude of the resultant vector is then given by Pythagorean's theorem:

R=\sqrt{R_x^2+R_y^2}

While the angle can be found by taking the arctangent of the ratio between the y-component and the x-component, mathematically:

tan \theta = \frac{R_y}{R_x}

Note that this angle is measured between the resultant vector and the positive direction of the x-axis.

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

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A car covers 120 km in 3 hours calculate its speed in m/s​
8_murik_8 [283]

Answer:

11.1 m/s

Explanation:

120 km = 120 x 1,000 = 120,000 m

3 hours = 3 x 60 x 60 = 3600 x 3 = 10,800 s

speed = 120,000 / 10,800

= 1200/108

= 11.1 m/s

6 0
2 years ago
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lora16 [44]

Answer:

H₀ = 1.6 x 10⁻¹⁸ s⁻¹

Explanation:

The Hubble's Constant can be found by the following formula:

v = H_o D\\\\H_o = \frac{v}{D}

where,

H₀ = Hubble's Constant = ?

v = speed of galaxy = 30000 km/s = 3 x 10⁷ m/s

D = Distacance = 600 Mpc = (6 x 10⁸ pc)(3.086 x 10¹⁶ m/1 pc)

D = 18.52 x 10²⁴ m

Therefore,

H_o = \frac{3\ x\ 10^7\ m/s}{18.52\ x\ 10^{24}\ m}

<u>H₀ = 1.6 x 10⁻¹⁸ s⁻¹</u>

3 0
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PV= nRT

Pressure is constant

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3 years ago
A stone tumbles into a mine shaft and strikes bottom after falling for 4.2 second how deep is the mine shaft
rjkz [21]
4.2*9.8\\41.16

41.16 meters
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3 years ago
Why pressure above the surface is greater than in the air​
nexus9112 [7]

Answer:

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Explanation:

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