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lubasha [3.4K]
3 years ago
13

How can we determine the angle of a resultant vector

Physics
1 answer:
klasskru [66]3 years ago
8 0

The angle of a resultant vector is given by the equation tan \theta = \frac{R_y}{R_x}

Explanation:

When we compute the resultant vector starting from 2 (or more) vectord, we add the components along the x- and y- direction of the original vectors, in order to find the component of the resultant vector along the two directions.

Let's call:

R_x the component of the resultant vector along the x-direction

R_y the component of the resultant vector along the y-direction

The magnitude of the resultant vector is then given by Pythagorean's theorem:

R=\sqrt{R_x^2+R_y^2}

While the angle can be found by taking the arctangent of the ratio between the y-component and the x-component, mathematically:

tan \theta = \frac{R_y}{R_x}

Note that this angle is measured between the resultant vector and the positive direction of the x-axis.

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

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Answer:

1.69\cdot 10^{10}J

Explanation:

The total energy of the satellite when it is still in orbit is given by the formula

E=-G\frac{mM}{2r}

where

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r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:

r=R+h=6370 km +575 km=6945 km=6.95\cdot 10^6 m

So the initial total energy is

E_i=-(6.67\cdot 10^{-11})\frac{(525 kg)(5.98\cdot 10^{24} kg)}{2(6.95\cdot 10^6 m)}=-1.51\cdot 10^{10}J

When the satellite hits the ground, it is now on Earth's surface, so

r=R=6370 km=6.37\cdot 10^6 m

so its gravitational potential energy is

U = -G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(525 kg)(5.98\cdot 10^{24}kg)}{6.37\cdot 10^6 m}=-3.29\cdot 10^{10} J

And since it hits the ground with speed

v=1.90 km/s = 1900 m/s

it also has kinetic energy:

K=\frac{1}{2}mv^2=\frac{1}{2}(525 kg)(1900 m/s)^2=9.48\cdot 10^8 J

So the total energy when the satellite hits the ground is

E_f = U+K=-3.29\cdot 10^{10}J+9.48\cdot 10^8 J=-3.20\cdot 10^{10} J

So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite:

\Delta E=E_i-E_f=-1.51\cdot 10^{10} J-(-3.20\cdot 10^{10} J)=1.69\cdot 10^{10}J

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Answer:

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Explanation:

Hello,

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